Assume the cost of an extended 100,000 mile warranty for a particular SUV follows the normal distribution with a mean of $1840 and a standard deviation of $60. ***Type integers or decimals. Using ascending order*** Assume the cost of an extended 100,000 mile warranty for a particular SUV follows the normal distribution with a mean of $1,840 and a standard deviation of $60. Complete parts (a) through (d) below.a) Determine the interval of warranty costs from various companies that are one standard deviation around the mean.The interval of warranty costs that are one standard deviation around the mean ranges from $ to $(Type integers or decimals. Use ascending order.)b) Determine the interval of warranty costs from various companies that are two standard deviations around the mean.The interval of warranty costs that are two standard deviations around the mean ranges from $ to $(Type integers or decimals. Use ascending order.)c) Determine the interval of waranty costs from various companies that are three standard deviations around the mean.The interval of warranty costs that are three standard deviations around the mean ranges from $ to $(Type integers or decimals. Use ascending order.)d) An extended 100,000 mile warranty for this type of vehicle is advertised at $2,080. Based on the previous results, what conclusions can you make?O A. The $2,080 cost of this warranty is much higher than average due to the fact that it is more than three standard deviations above the mean.O B. This warrantybetter quality than warranties offered by competing companies due to the fact that it is more than three standard deviations above the mean.O C. The $2,080 cost of this warranty must be an error in the advertisement because a data value cannot be more than three standard deviations from the mean,O D. The $2,080 cost of this warranty is slightly higher than average due to the fact that it is more than three standard deviations above the mean.

We need to perform this calculation: mean +/-SD a) mean +/-SD = 1450+/-80 = (1370, 1530) b) for mean…

Uton witn a mt Assume the cost of an extended 100,000 mile warranty for a particular SUV lollows the nomal dist a) Determine the interval of warranty costs from various companies that are one standard deviation around the mean. The interval of warranty costs that are one standard deviation around the mean ranges from $ to $. (Type integers or decimals. Use ascending order.) b) Determine the interval of warranty costs from various companies that are two standard deviations around the mean. The interval of warranty costs that are two standard deviations around the mean ranges from $ to $. (Type integers or decimals. Use ascending order.) c) Determine the interval of warranty costs from various companies that are three standard deviations around the mean. The interval of warranty costs that are three standard deviations around the mean ranges from $ to $ (Type integers or decimals. Use ascending order.) d) An extended 100,000 mile warranty for this type of vehicle is advertised at $2,080. Based on the previous results, what conclusions can you make? O A. The $2,080 cost of this warranty is much higher than average due to the fact that it is more than three standard deviations above the mean. O B. This warranty is better quality than warranties offered by competing companies duo to tho fonot th

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume the cost of an extended 100,000 mile warranty for a particular SUV follows the normal distribution with a mean of $1840 and a standard deviation of $60. ***Type integers or decimals. Using ascending order***

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

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