Based on the results of the previous question, calculate the values of the frictional forces provided by catcher 1 and catcher 2 as the lightest spherical object hits it and eventually stops. (Each catcher will have three values since there are 3 distances) SPEHRICAL OBECT 1 MASS (kg)0.0022SPEHRICAL OBECT 2 MASS (kg)0.0031SPEHRICAL OBECT 3 MASS (kg)0.0053SET-UP 1 AND 2 (LIGHTEST MASS AT DIFFERENT LENGTHS WITH CATCHERS 1 AND 2)Time from top to end of ramp andcorresponding accelerationsTrials for 10 cm Catcher 1 Knock-Trials for 20 cmCatcher 1 Knock-Trials for 30 cmCatcher 1 Knock-ConfigurationsTime 1Time 2Time 3Ave.ramp distanceback Distanceramp distanceback Distanceramp distanceback Distance10 cm ramp distance0.350.480.560.46122Calculated Acceleration1.630.870.641.051222320 cm ramp distanceCalculated Acceleration30 cm ramp distanceCalculated Acceleration0.730.560.640.643131330.751.280.981Ave.1Ave.1.67Ave.2.670.810.560.680.680.911.911.31.4Catcher 2 Knock-Catcher 2 Knock-Catcher 2 Knock-Trials for 10 cm back DistanceTrials for 20 cmback DistanceTrials for 30 cmback Distanceramp distance(cm)ramp distance(cm)ramp distance(cm)rce calculation 10 cm ramp distar 0.00231rce calculation 20 cm ramp distar 0.0031rce calculation 30 cm ramp distar 0.00742110.713.120.623.3330.432Ave.Ave.0.57Ave.2.8SET-UP 3 & 4 (2 OTHER SPHERICAL OBJECTS WITH CATCHER 1 AT 10 CM)SHPERICALlOBJECT NO.SHPERICAL2ОBJЕCT NO.3Catcher 1 Knock-Catcher 1 Knock-Trials for 10 cm back DistanceTrials for 10 cmback Distanceramp distance(cm)ramp distance(cm)121.32.0.621.53231Ave.1.53Ave.1.27

Given that the mass of lightest object is 0.015 kg.

Answered: st sp | bartleby

Similar questions

As shown in the figure below, a box of mass m = 59.0 kg (initially at rest) is pushed a distance d = 80.0 m across a rough warehouse floor by an applied force of FA = 220 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) (a) work done by the applied force WA = (b) work done by the force of gravity Wg = (c) work done by the normal force WN = (d) work done by the force of friction Wf = rough surface www (e) Calculate the net work on the box by finding the sum of all the works done by each individual force. W Net = J (f) Now find the net work by first finding the net force on the box, then finding the work done by this net force. W Net =
A box of mass 5.9 kg is sliding down a ramp, as shown in the picture. The coefficient of kinetic friction between the ramp and the box is 0.4, while the angle of the ramp with the ground is 30°. What is the size of the friction force?
Please circle answers
In the figure, the 200-lb crate is being pulled up the slope by the motor M. If the velocity of the point P is 2s³ ft/s (where s is the displacement of the crate), and the coefficient of kinetic friction between the crate and the slope is u = 0.2, what will the towing force applied by M be when the box has moved 10 ft up the slope?
As shown in the figure below, a box of mass m = 68.0 kg (initially at rest) is pushed a distanced = 69.0 m across a rough warehouse floor by an applied force of F = 236 N directed at an angle of 30.0° below the horizontal. The coefficient of kinetic friction between the floor and the box is 0.100. Determine the following. (For parts (a) through (d), give your answer to the nearest multiple of 10.) F 30 rough surface Iwwwwwwwwwwww (a) work done by the applied force WA = (b) work done by the force of gravity (c) work done by the normal force WN = (d) work done the force of friction W; = (e) Calculate the net work on the box by finding the sum of all the works done by each individual force. WNet = (f) Now find the net work by first finding the net force on the box, then finding the work done by this net force. WNet = Additional Materials O Reading
Can you check my answers? Dynamics
I was given this problem, and I don't really know what to do about the fact that the normal force doesn't equal the weight for this problem. How am I supposed to find the kinetic friction coefficient now? A box of mass 2,463g is on level ground being pulled by a force of 6.41N at angle 47.2 above horizontal. If the block is moving with a constant velocity, what is the kinetic friction coefficient? (Hint: the normal force does not always equal the weight; it does not in this case.)
In the very Dutch sport of Fierljeppen, athletes run up to a long pole and then use it to vault across a canal as shown in (Figure 1). At the very top of his arc, a 70 kg vaulter is moving at 2.9 m/s and is 5.5 m from the bottom end of the pole. What is the magnitude of the vertical force that the pole exerts on the vaulter? Express your answer with the appropriate units.
In the friction experiment, if the friction block has a mass of 599 g, and it started to move at a constant speed after giving it a slight push when the mass in the hanger is 284 g (including the hanger), what is the coefficient of kinetic friction?
A skydiver weighing 65 kg jumps out of a helicopter hovering at a height of 3 kilometers. Assume a cross-sectional area of 0.5 square meters. After thirty seconds of free fall, the skydiver deploys the parachute and the cross-sectional area becomes 40 square meters. Reproduce the model for the skydiver in Excel or VenSim. In VenSim you may have to make At quite small in order not to throw an error. Because you reach terminal velocity relatively quickly your answer should not be particularly sensitive to the value of At you choose. What is the skydiver's terminal velocity without the parachute? meters/second What is the skydiver's terminal velocity with the parachute? meters/second
an object with mass m shown in the figure is attached to a spring with a spring constant k in a horizontal arrangement without friction, and the object is compressed as much as d. After the system is released, the object can rise to the height of h in the friction inclined plane. find the coefficient of kinetic friction between the oblique order and the body?
A block of mass m rests on a plane inclined an angle with the horizontal. A spring with force constant k is attached to the block. The coefficient of static friction between the block and plane is  s. The spring is pulled upward along the plane very slowly. (a) What is the extension of the spring the instant the block begins to move? (b) The block stops moving just as the extension of the contracting spring reaches zero. Express k (the kinetic coefficient of friction) in terms of s and .

SEE MORE QUESTIONS