Horizontal air wind turbine (HAWT) has the following data, height of tower =10
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Horizontal air wind turbine (HAWT) has the following data, height of tower =100 m, diameter of rotor = 80 m, determine the power extracted by the turbine, if the wind speed at this height is 15 m/sec and reduced by 20 %, suppose the air density is 1.3 kg/m3
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- What is irreversible head loss? How is it related to the mechanical energy loss?(a) A steel ball of mass 0.2 kg is projected vertically upwards, from the top of a building 100 m high, with an initial velocity of 40 m.s. Ignore air frietion and calculate: i. the total mechanical energy of the ball the time it was projected. ii. the total mechanical energy of the ball the time it reached the ground level (i.e at the bottom of the building) -1 iii. the total mechanical energy of the ball the time it reaches its maximum height above the ground. iv. the velocity of the ball the time it reached the ground level v. time taken by the ball to reach the ground level from the time it was projected vi. the maximum height above the ground the ball reached vii. the velocity of the ball the time it was 20 m above the ground (b) Two objects of mass 12 kg and 8 kg respectively move towards each other at velocities 10 m.s and 5 m.s respectively. If the objects unite during collision, calculate the resultant velocity. Page 5(b) State Betz's law. (c) A horizontal wind turbine has blades 30 m radius. Calculate the captured power if the maximum power coefficient is 32%, wind speed is 8 m/s, and air density is 1.2 kg/m. [Note that is P = C,PAV³ where P = Captured power, C- Maximum power coefficient, p= Air density, A = Rotor swept area, and V Wind speed.]
- Commercially available large wind turbines have blade span diameters larger than 100 m and generate over 3 MW of electric power at peak design conditions. Consider a wind turbine with a 60-m blade span subjected to 30-km/h steady winds. If the combined turbine–generator efficiency of the wind turbine is 32 percent, determine (a) the power generated by the turbine and (b) the horizontal force exerted by the wind on the supporting mast of the turbine. Take the density of air to be 1.25 kg/m3, and disregard frictional effects on mast.Q3. An aircraft having a take-off mass of 36500 kg and a wing area of 95 m² fitted with turboprop engines of total power 10000 kW, assumed not to vary with speed, and propellers of 87 per cent efficiency. The drag polar for the aircraft is: C₂-0.0145+0.052C₂² At sea level: (a) Calculate the coefficient of lift at minimum required power, associated speed and the minimum power required for steady level flight. (b) Calculate the maximum rate of climb and angle of climb available to the pilot.The energy of a system always remains ?constant. always increases . decreases when work is done on the system . decreases when work is done by the system .
- A cylindrical tank, shown in the figure, has height 8 m and radius 4 m. Suppose the water tank is half-full of water. Determine the work required to empty the tank by pumping the water to a level 6 m above the top of the tank. Use 1000 kg/m³ for the density of water and 9.8 m/s² for the acceleration due to gravity. 4 m Draw a y-axis in the vertical direction (parallel to gravity) and choose the center of the bottom of the tank as the origin. For 0 ≤ y ≤8, find the cross-sectional area A(y). A(y) = (Type an exact answer, using as needed.) 8 mIs it experimentally possible that the energy absorbed by the cylinder due to friction could be greater than the work performed on it? Explain.1. A 23.0 kg child is playing on a swing with a length of 2.5 m. If the swing starts from rest and makes an angle of 40.0◦ with the vertical at the top of the swing, a) determine the child’s speed at the bottom of the swing neglecting friction. b) If the swing has a speed of 2.8 m/s at the bottom, determine the work done by friction during the downswing and, bonus) assuming the force of friction is constant, determine the maximum angle the swing attains on the upswing after passing through the bottom. Hint: Use the approximation that cos θ ≈ 1 − 1 2 θ 2 for angles given in radians.