spring allowing the skater to oscillate back and forth. The skater (mass=60kg) is stretched 0.84m from equilibrium with a force 250N and remains at rest. At 0.84m from equilibrium, the skater is then pushed toward the equilibrium position. At a distance of 0.22m (from equilibrium), the skater has a speed of 2.4m/s b) Write down the equation describing the skater's position as a function of time (assume t=0 at 0.22m and motion is in the negative x-direction). Your solution should have numeric values for the variables.
spring allowing the skater to oscillate back and forth. The skater (mass=60kg) is stretched 0.84m from equilibrium with a force 250N and remains at rest. At 0.84m from equilibrium, the skater is then pushed toward the equilibrium position. At a distance of 0.22m (from equilibrium), the skater has a speed of 2.4m/s b) Write down the equation describing the skater's position as a function of time (assume t=0 at 0.22m and motion is in the negative x-direction). Your solution should have numeric values for the variables.
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![spring allowing the skater to oscillate back and forth. The skater (mass=60kg) is stretched 0.84m from
equilibrium with a force 250N and remains at rest. At 0.84m from equilibrium, the skater is then pushed
toward the equilibrium position. At a distance of 0.22m (from equilibrium), the skater has a speed of 2.4m/s b)
Write down the equation describing the skater's position as a function of time (assume t=0 at 0.22m and
motion is in the negative x-direction). Your solution should have numeric values for the variables.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3614a9ba-5d2e-463c-b206-803d5163a55b%2F90507f0b-bf97-45a9-9a56-5d92aaa1fd98%2F4rw3ylc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:spring allowing the skater to oscillate back and forth. The skater (mass=60kg) is stretched 0.84m from
equilibrium with a force 250N and remains at rest. At 0.84m from equilibrium, the skater is then pushed
toward the equilibrium position. At a distance of 0.22m (from equilibrium), the skater has a speed of 2.4m/s b)
Write down the equation describing the skater's position as a function of time (assume t=0 at 0.22m and
motion is in the negative x-direction). Your solution should have numeric values for the variables.
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