Speaking of Mercury, approximately how long is one year on the planet closest to theSun? The sizes of the objects in our model of the solar system are not to scale; however,the relative orbital periods around the Sun are. So you can answer this question bycounting the revolutions of Mercury during one Earth year.a) Approximately 90 Earth daysb) Approximately 370 Earth daysc) Approximately 120 Earth daysd) Approximately 50 Earth days

Kepler's Third Law of Planetary Motion, also known as the Law of Harmonies, relates the orbital…

Answered: Speaking of Mercury, approximately how…

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A)At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law.
The solar system has a planet with an orbital period T1b=1.51d and an orbital radius of R1b=1.6456x10^6km. Another planet in the system has an orbital radius of R1f=5.5352x10^6 km. Calculate its orbital period in days.
An object has recently been discovered orbiting the Sun. The following is known about this object. Images indicate it is about 800 km in diameter, appears to be covered in craters, and has a mostly spherical shape. The object was discovered at 42 AU from the Sun, which was found to be the perihelion of its orbit. The aphelion of its orbit was found to be 330 AU. a) From this information determine the semi-major axis and period of the orbit. b) Classify the object according to the definitions from the 2006 IAU meeting and describe the area of the Solar System from which it comes.
Given the orbital radius and period of a moon, derive an algebraic solution for the mass of the planet that moon orbits. Watch those units, convert to SI.
Kepler's 1st law says that our Solar System's planets orbit in ellipses around the Sun where the closest distance to the Sun is called perihelion. Suppose I tell you that there is a planet with a perihelion distance of 2 AU and a semi-major axis of 1.5 AU. Does this make physical sense? Explain why or why not.
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Use Kepler's Law, which states that the square of the time, T, required for a planet to orbit the Sun varies directly with the cube of the mean distance, a, that the planet is from the Sun.Using Earth's time of 1 year and a mean distance of 93 million miles, the equation relating T (in years) and a (in million miles) is 804375T2=a3.Use that relation equation to determine the time required for a planet with mean distance of 206 million miles to orbit the Sun. Round to 2 decimal places. years
The Earth has a mass of 5.97 * 1024 kg and the Moon has a mass of 7.35 * 1022 kg. If they are separated by a distance of 3.85 * 105km, what is the force (in N) between the Earth and the Moon? (Enter your answer in scientific notation: 1.23E12 means 1.23 * 1012)
The Earth has a mass of 5.97 * 1024 kg and the Moon has a mass of 7.35 * 1022 kg. If they are separated by a distance of 3.85 * 105 km, what is the force (in N) between the Earth and the Moon? (Enter your answer in scientific notation: 1.23E12 means 1.23 * 1012)
Consider a planet of radius 10 x 106 m for which the length of a sidereal day is 5 x 104 s. Calculate the speed you would have with respect to the center of the planet, in m/s, if you were at a latitude of 5 degrees north. (Please answer to the fourth decimal place - i.e 14.3225)
The average distance between the Sun and Mars is 2.3×1011m2.3×1011m. F = ? Express your answer with the appropriate units.