At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law.

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A)At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law. 

 

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Concept and Principle:

A satellite in a geostationary orbit will move in the same direction and with the same period around the planet. In mars, it is known as areostationary orbit. The radius of such an orbit is given by,

R=GmmarsTmars24π23

Where G is the universal gravitational constant, Tmars is the rotational period of the mars and mmars mass of Mars.

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