The radius of the Earth's orbit is 1.50 1011 m and that of Mars is 2.28 1011 m. The star that this planet orbits is identical to our Sun. What is the orbital period of this planet?In years?
Q: If the mass of Jupiter is defined as 1 MJ = 1.90 ✕ 1027 kg, what is the mass of Saturn (5.68 ✕ 1026…
A: Given data' The mass of Jupiter is defined as, 1 MJ = 1.90 x 1027 kg. The mass of Saturn is given as…
Q: What is the distance from an asteroid to a sun
A:
Q: A planet is about 7.79 x 108 km (orbital radius) from the sun. It takes 1,425 days for the planet to…
A:
Q: 1000 kg satellite orbits the earth with a speed of 9997 m/sm/s. What is the radius of the orbit?…
A:
Q: A LEO satellite was launched into an orbit at an altitude of 1000 km. The satellite orbits the earth…
A: The Leo satellite was launched into an orbit at an height given as, h=1000 km, The radius of the…
Q: GPS (Global Positioning System) satellites orbit at an altitude of 2.3x107 m. Part A Find the…
A:
Q: A planet of mass 5.8 x 1024 kg orbits a star of mass 1.6 x 1030 kg in a circular orbit 10 x 1011 m…
A:
Q: Approximately one billion years ago, the Moon orbited the Earth much closer that it does today. The…
A: The equation to calculate linear velocity in a circular orbit is given by: v=2πRT Here, v is the…
Q: The time separating high tides is 12 hours and 25 minutes. Assume that the high tide occurs at 2:18…
A: (a) Since the time separating high tides is 12 hours and 25 minutes, and the high tide occurs at…
Q: Assume the earth's mass is 73.13 x 1025 kg, and radius is 27.06 x 103 miles, what would be the…
A: Given data: Mass (M) = 77.13 × 1025 kg Radius (r) = 27.06 × 103 miles G = 6.67 × 10-11 Nm2/kg2…
Q: One of the first things you learn in physics class is the law of universal gravitation, F = G (m1m2…
A: (a)According to Newton’s law of gravitation Where, G=universal Gravitation constant m1=mass of the…
Q: Two exoplanets, UCF1.01 and UCF1.02 are found revolving around the same star. The period of planet…
A:
Q: A planet of mass m = 6.35 x 1024 kg orbits a star of mass M = 1.85 × 1029 kg in a circular path. The…
A:
Q: If a planet with 8.1 times the mass of Earth was traveling in Earth's orbit, what would its period…
A: According to KEPLER'S THIRD LAW Period of planet is cube of semimajor axis. Period is related with r…
Q: On the surface of the Moon an astronaut has a weight of Fg = 190 N. The radius of the Moon is Rm =…
A:
Q: Find the ratio of the mass of Jupiter to that of the Earth based on data in this table.
A: Given : 1 km3/year2 = 1.0041778 x 10-6 m3/s2 For Earth, r 3T 2 = 1.01 x 1019…
Q: A planet with mass 8.07x1023 kg orbits a star with mass 1.18x1030 kg. The orbit is circular, and the…
A:
Q: On Earth, a 58 kg astronaut weighs 568.4 Newtons. What would she weigh if she landed on Jupiter's…
A: Given:Mass of Io = Radius of Lo= The gravitational acceleration at Lo is calculated as:Plugging…
Q: Planet X orbits the star Omega with a "year" that is 492 days long. Planet Y circles Omega at four…
A: Given: Planet X orbits the star Omega with a "year" that is 492 days long. Planet Y circles Omega…
Q: A planet of mass ?=7.75×1024 kg orbits a star of mass ?=1.35×1029 kg in a circular path. The radius…
A: mass of planet = 7.75×1024 kg mass of star = 1.35×1029 kg radius of orbit = 6.15×010 m
Q: A planet with mass 4.83x1023 kg orbits a star with mass 6.95x1030 kg. The orbit is circular, and the…
A: Given Mass of the star is M=6.95×1030 kg Universal gravitational constant is G=6.67×10-11 N.m2/kg2…
Q: Ganymede is a moon of Jupiter (mass = 1.90 x 1027 kg). It orbits Jupiter in a circle of radius 1.07…
A: Given Mass of Jupiter M =1.9*1027 kg Radius r = 1.07*109 m
Q: The radius of the Earth's orbit is 1.50 1011 m and that of Mars is 2.28 1011 m. The star that this…
A: The expression for the orbital period,
Q: © Macmillan Learning A horizontal meter stick has a mass of 211 g. Three weights ride on the meter…
A:
Q: In the year 8000 (Y8K) the mass of the Earth has increased (due to excessive space mining). As a…
A:
Q: What is the mass of the sun if the radius is 7.1*10^8 and the gravitational acceleration is 270?…
A: Write the given value of this question, Radius of sun is, R=7.1×108m Gravitational acceleration is,…
Q: ets are in orbits that are similar to that of earth, which orbits the sun (MsunMsun = 1.99× 10^30kg)…
A:
Q: There is a planet X that has a mass that is 24 times that of the earth and 4 times the earth's…
A:
Q: In this problem, we will directly calculate the surface gravity and your weight on another planet.…
A: (a) The formula to calculate the surface gravity of the planet is gv=GMvrv where gv is the surface…
Q: Astronomical observations of our milky way galaxy indicate that it has a mass of about 8x1011 solar…
A: 1 solar mass = 1.989e+30 kg 1 Light year = 9.461e+15 m Given, mass of milky way is M = 8x1011 solar…
Q: The radius of the Earth R_{E} = 6.378 * 10 ^ 6 m and the acceleration due to gravity at its surface…
A: The acceleration due to gravity at an altitude h above the surface of the earth is given by…
Q: Calculate mass of the Earth
A: Answer : Consider the mass of the earth is M , mass of the moon is m , the average distance from…
Q: Assume the earth's mass is 31.589 x 1025 kg, and radius is 60.9 x 103 miles, what would be the…
A:
Q: Assume the earth's mass is 85.47 x 1025 kg, and radius is 51.93 x 103 miles, what would be the…
A: Data provided: Mass (M) = 85.47 × 1025 kg Radius (r) = 51.93 × 103 miles G = 6.67 × 10-11 Nm2/kg2…
The radius of the Earth's orbit is 1.50 1011 m and that of Mars is 2.28 1011 m. The star that this planet orbits is identical to our Sun. What is the orbital period of this planet?In years?
Step by step
Solved in 2 steps
- According to Lunar Laser Ranging experiments the average distance LM from the Earth to the Moon is approximately 3.85 x 105 km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). a) Calculate the orbital velocity of the Moon. b) Calculate mass of the Earth.A planet of mass m= 8.45 x 1024 kg is orbiting in a circular path a star of mass M= 6.95 x 1029 kg. The radius of the orbit is R= 3.15 x 107km. What is the orbital pperiod (in Earth days) of the planet Pplanet? Express your answer to three significant figures. Pplanet = ? daysA planet with mass 9.69x1023 kg orbits a star with mass 9.21x1030 kg. The orbit is circular, and the distance from the planet to the sun is 225x106 km. What is the length of a year on this planet? Give your answer in earth years (1 earth year = 31,557,600 seconds).
- The mean distance of an asteroid from the Sun is 1.74 times that of Earth from the Sun. From Kepler's law of periods, calculate the number of years required for the asteroid to make one revolution around the Sun.Assume the earth's mass is 23.335 x 1025 kg, and radius is 76.394 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.An earth-like planet has a mass of 6.00×1024 kg and a radius of 7000 km. A satellite of mass 55 kg is orbiting the planet at a distance of 2000 km above the surface. What is the magnitufe of the gravitational force exerted on the satellite by the planet? (We can simplify the Gravitational Constant G to 6.7x10-11 Nm2/kg) Submit Answer Tries 0/2 What is the magnitude of the force exerted on the planet by the satellite?
- Assume the earth's mass is 55.818 x 1025 kg, and radius is 10.63 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.The mass of planet X is 6.4 x 1023 kg and the aceleration of gravity on its surface is 3.7 m/s², if the gravitational constant G = 6.67 x 10-11 N.m²/kg², the radius of this planet R is a) 3.40 x 106 m c) 4.03 x 106 m e) 1.15 x 1013 m b) 2.98 x 106 m d) 7.56 x 106 m.Assume the earth's mass is 80.004 x 1025 kg, and radius is 35.532 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.
- The radius of the Earth's orbit is 1.50 x 1011 m and that of Neptune is 4.52 x 1012 m. The star that this planet orbits is identical to our Sun. What is the orbital period of this planet? 2.2 years eBookAccording to Lunar Laser Ranging experiment the average distance LM from the Earth to the Moon is approximately 3.91 x 105 km. The Moon orbits the Earth and completes one revolution relative to the stars in approximately 27.5 days (a sidereal month). Calculate the orbital velocity of the Moon in m/s. Answer: Choose...The moon's period of revolution around the Earth is 27.3 d. How far away is the moon from the surface of the Earth? O A) 1.33× 107 m B) 3.83 × 108 m C) 3.77 × 108 m D) 4.88 × 10⁹ m