Spam: A researcher reported that 71.8 % of all email sent in a recent month was spam. A system manager at a large corporation believes that the percentage at his company may be 69%. He examines a random sample of 500 emails received at an email server, and finds that 365 of the messages are spam. Can you conclude that greater than 69% of emails are spam? Use both a-0.01 and a= 0.05 levels of significance and the critical value method with the table. Part 1 of 5 State the appropriate null and alternate hypotheses. Ho: p - .69 H: p> .69 This hypothesis test is a right-tailed V test. Part 2 of 5 Find the critical values. Round the answers to three decimal places. For a-0.01 , the critical value is 2326 For a=0.05 , the critical value is 1.645 Part 3 of 5 Compute the test statistic. Do not round intermediate calculations. Round the answer to two decimal places. 1.93 Part: 3/5 Part 4 of 5 Determine whether to reject Ho. At the a-0.01 level, (Choose one) ▼ the null hypothesis H. At the a-0,05 level, (Choose one) ▼ the null hypothesis Ho:

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Spam: A researcher reported that 71.8 % of all email sent in a recent month
manager at a large corporation believes that the percentage at his company may be 69%. He
examines a random sample of 500 emails received at an email server, and finds that 365 of the
messages are spam. Can you conclude that greater than 69% of emails are spam? Use both a-0.01
and a= 0.05 levels of significance and the critical value method with the table.
was spam. A system
Part 1 of 5
State the appropriate null and alternate hypotheses.
Ho: p - .69
H: p>.69
This hypothesis test is a right-tailed
test.
Part 2 of 5
Find the critical values. Round the answers to three decimal places.
For a= 0.01 , the critical value is 2.326
For a=0.05 , the critical value is 1.645
Part 3 of 5
Compute the test statistic. Do not round intermediate calculations. Round the answer to two
decimal places.
1.93
Part: 3/5
Part 4.of 5
Determine whether to reject Ho.
At the a=0.01 level, (Choose one) ▼ the null hypothesis H.
At the a=0,05 level, (Choose one) ▼ the null hypothesis H.
Transcribed Image Text:Spam: A researcher reported that 71.8 % of all email sent in a recent month manager at a large corporation believes that the percentage at his company may be 69%. He examines a random sample of 500 emails received at an email server, and finds that 365 of the messages are spam. Can you conclude that greater than 69% of emails are spam? Use both a-0.01 and a= 0.05 levels of significance and the critical value method with the table. was spam. A system Part 1 of 5 State the appropriate null and alternate hypotheses. Ho: p - .69 H: p>.69 This hypothesis test is a right-tailed test. Part 2 of 5 Find the critical values. Round the answers to three decimal places. For a= 0.01 , the critical value is 2.326 For a=0.05 , the critical value is 1.645 Part 3 of 5 Compute the test statistic. Do not round intermediate calculations. Round the answer to two decimal places. 1.93 Part: 3/5 Part 4.of 5 Determine whether to reject Ho. At the a=0.01 level, (Choose one) ▼ the null hypothesis H. At the a=0,05 level, (Choose one) ▼ the null hypothesis H.
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