Solve. Let f(x)= kx for x 2,3,4. Find k so that the function of f (x) satisfies the two properties of a probability mass function.

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Author:Amos Gilat
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Chapter1: Starting With Matlab
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ifxe(1,2,3,...,9)
6. P(X = x) =285
0,
%3D
otherwise.
B. Solve.
7. Let f(x) = kx for x 2,3,4. Find k so that the function of f(x) satisfies the
two properties of a probability mass function.
8. Let X be a discrete random variable. Let its Support S be the set of the first
ten natural numbers. Given the pmf of X:
x,
55
if x e S
%3D
0,
if x 4 S
Compute the probability P(X > 7).
9. Let X be a discrete random variable with Support S = {1,2,3, ... ,12}.
Its pmf is given below:
1.
x,
0,
Compute the probability P(X > 8).
10. Graph the probability mass function below:
P(X x) =
if x e Support S
%3D
%3D
if x # Support S
1.
if x e S
%3D
(x)f
if x S
C. Compute the expected value of the discrete random variable
11. Let X be a discrete random variable with Support S {1,2,3,4}. Its pmf is
given below.
f(x) = 4
if x e the Support S
-X,
%3D
0,
if x the Support S
12. Let X be a discrete random variable with Support S {1,2}. Its pmf is given
below.
if x e the Support S
%3D
if x the Support S
13. Let X be a discrete random variable with Support S {1,2,3,4}. Its pmf is
given below.
%3D
if x e the Support S
%3D
(x)
(0,
14. Let X be a discrete random variable with Support S {1,2,3,4,5,6,7}. Its pmf
if x the Support S
%3D
is given below.
3D(x))
8.
if x e the Support S
if x # the Support S
15. Let X be a discrete random variable with Support S {1,2,3,4,5,6,7,8}. Its
%3D
pmf is given below.
Transcribed Image Text:drive.google.com Done ifxe(1,2,3,...,9) 6. P(X = x) =285 0, %3D otherwise. B. Solve. 7. Let f(x) = kx for x 2,3,4. Find k so that the function of f(x) satisfies the two properties of a probability mass function. 8. Let X be a discrete random variable. Let its Support S be the set of the first ten natural numbers. Given the pmf of X: x, 55 if x e S %3D 0, if x 4 S Compute the probability P(X > 7). 9. Let X be a discrete random variable with Support S = {1,2,3, ... ,12}. Its pmf is given below: 1. x, 0, Compute the probability P(X > 8). 10. Graph the probability mass function below: P(X x) = if x e Support S %3D %3D if x # Support S 1. if x e S %3D (x)f if x S C. Compute the expected value of the discrete random variable 11. Let X be a discrete random variable with Support S {1,2,3,4}. Its pmf is given below. f(x) = 4 if x e the Support S -X, %3D 0, if x the Support S 12. Let X be a discrete random variable with Support S {1,2}. Its pmf is given below. if x e the Support S %3D if x the Support S 13. Let X be a discrete random variable with Support S {1,2,3,4}. Its pmf is given below. %3D if x e the Support S %3D (x) (0, 14. Let X be a discrete random variable with Support S {1,2,3,4,5,6,7}. Its pmf if x the Support S %3D is given below. 3D(x)) 8. if x e the Support S if x # the Support S 15. Let X be a discrete random variable with Support S {1,2,3,4,5,6,7,8}. Its %3D pmf is given below.
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