Solve the following system of equations for forces BC and BD. 3 m 3 m -4 m→-4 m→-4 m- 1.75 kN 2 kN 1.5 kN 2 kN F 1 kN 0.75 kN G 6 m B C E - 6 m - 6 m - - 6 m 0 =7.83 4.5 +BC -2-BD 는 0 = 2.8 4.5 0 =7.83 4.5

Q: me beam shown ists of a 200 GPa; /= 1120 × 106 mm4]. If w= 66 kN/m and P= 128 kN, determine: AY, V P…

A: The beam shown in Figure Q.2 consists of a W610 × 140 structural steel wide-flange shape [E = 200…

Q: Consider the beam shown in (Figure 1). Suppose that w=2.4 k/ft. Figure L. -9 ft 1 of 1 W ▼ Part A…

A:

Q: Calculate the moment of inertia about centroidal axis.

A: In the given image, b=159 mm d=216 mm t=37.4 mm

Q: Given that P = 980 lb and Q = 79 lb. Determine the resultant of the two forces.

A: Please find the attachment.Explanation:Step 1:

Q: Find the spring force if EI= 2*108 kN.cm² and the Flexibility of the spring P = 0.125 cm/kN. 2kN/m a…

A: Given a beam 'a b c' as shown in figure with EI = 2 × 108 KN- cm2  Flexibility of spring = 0.125…

Q: 2.38 A rectangular gate having a width of 4 ft is located in the sloping side of a tank as shown in…

A: Given: Hinge at the top of the gate. Width of rectangular gateB=4 ft. Length of rectangular gateL=6…

Equilibrium and Support Reactions

Civil engineers deal with structures that are composed of several members connected or with individual members such as beams and columns. To analyze such structures, the condition of statics must be applied. Under the static condition, the members are considered to be in equilibrium under the action of forces, that is, the members are assumed to be having negligible velocity.