me beam shown ists of a 200 GPa; /= 1120 × 106 mm4]. If w= 66 kN/m and P= 128 kN, determine: AY, V P A 1.5 m B W 3.5 m Tal Steel C numerator EI e-mange shape [2 2.5 m Figure Q.2 Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D. a) Calculate the value of the deflection at point B due to uniformly distributed load win the form D UB Note: E/will cancel out in further calculations. Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis. X
me beam shown ists of a 200 GPa; /= 1120 × 106 mm4]. If w= 66 kN/m and P= 128 kN, determine: AY, V P A 1.5 m B W 3.5 m Tal Steel C numerator EI e-mange shape [2 2.5 m Figure Q.2 Part A: The reactions at A, B, and D. Choose the reaction force at B as the redundant; therefore, the released beam is simply supported between A and D. a) Calculate the value of the deflection at point B due to uniformly distributed load win the form D UB Note: E/will cancel out in further calculations. Enter the numerator in the answer box below in kNm³ to three decimal places. Assume the positive direction of deflection in the positive direction of v axis. X
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Please see question d below and e and f in picture
d) Calculate the vertical reaction at support D. Enter your answer in kN to two decimal places.
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Step 1: Introducing given data
VIEWStep 2: Taking reaction at B as redundant
VIEWStep 3: Calculate vertical reaction at A for simply supported beam AD for udl & load
VIEWStep 4: Using double integration method to calculate deflection at B due to udl w
VIEWStep 5: Using double integration method to calculate deflection at B due to load P
VIEWStep 6: Using double integration method to calculate deflection at B due to reaction By
VIEWStep 7: Calculate reaction at B
VIEWStep 8: Calculation of maximum bending moment
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