**Solving for X-Intercepts of a Quadratic Function**Given the quadratic function:\[ f(x) = x^2 - 6x + 9 \]**Objective:** Find the x-intercepts.**Options:**- $ x = 3 $- $ x = -3 $ and $ 3 $- $ x = 9 $ and $ -6 $- $ x = -5 $ and $ -1 $**Solution Approach:**To find the x-intercepts, set the function equal to zero:\[ x^2 - 6x + 9 = 0 \]This can be factored as:\[ (x - 3)^2 = 0 \]Thus, the x-intercept is:\[ x = 3 \] Verify by substituting back into the original equation. The correct answer is $ x = 3 $.

Answered: Solve the following quadratic function…

Solve the following quadratic function to find the x-intercepts: f(x) = x² - 6x +9 x=3 x = -3 and 3 Ox= 9 and -6 O x = -5 and -1

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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Question

**Solving for X-Intercepts of a Quadratic Function**

Given the quadratic function:
\[ f(x) = x^2 - 6x + 9 \]

**Objective:** Find the x-intercepts.

**Options:**
- $ x = 3 $
- $ x = -3 $ and $ 3 $
- $ x = 9 $ and $ -6 $
- $ x = -5 $ and $ -1 $

**Solution Approach:**

To find the x-intercepts, set the function equal to zero:
\[ x^2 - 6x + 9 = 0 \]

This can be factored as:
\[ (x - 3)^2 = 0 \]

Thus, the x-intercept is:
\[ x = 3 \]

Verify by substituting back into the original equation. The correct answer is $ x = 3 $.

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