Solve the following quadratic function to find the x-intercepts: f(x) = x² - 6x +9 x=3 x = -3 and 3 Ox= 9 and -6 O x = -5 and -1
Solve the following quadratic function to find the x-intercepts: f(x) = x² - 6x +9 x=3 x = -3 and 3 Ox= 9 and -6 O x = -5 and -1
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE:
1. Give the measures of the complement and the supplement of an angle measuring 35°.
Related questions
Question
![**Solving for X-Intercepts of a Quadratic Function**
Given the quadratic function:
\[ f(x) = x^2 - 6x + 9 \]
**Objective:** Find the x-intercepts.
**Options:**
- \( x = 3 \)
- \( x = -3 \) and \( 3 \)
- \( x = 9 \) and \( -6 \)
- \( x = -5 \) and \( -1 \)
**Solution Approach:**
To find the x-intercepts, set the function equal to zero:
\[ x^2 - 6x + 9 = 0 \]
This can be factored as:
\[ (x - 3)^2 = 0 \]
Thus, the x-intercept is:
\[ x = 3 \]
Verify by substituting back into the original equation. The correct answer is \( x = 3 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2e1cb03f-91d2-4991-91c8-37c8965f1bd7%2Feb5ae719-f2c2-4154-b8d6-d5a464d2e358%2Fcj4w7oo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Solving for X-Intercepts of a Quadratic Function**
Given the quadratic function:
\[ f(x) = x^2 - 6x + 9 \]
**Objective:** Find the x-intercepts.
**Options:**
- \( x = 3 \)
- \( x = -3 \) and \( 3 \)
- \( x = 9 \) and \( -6 \)
- \( x = -5 \) and \( -1 \)
**Solution Approach:**
To find the x-intercepts, set the function equal to zero:
\[ x^2 - 6x + 9 = 0 \]
This can be factored as:
\[ (x - 3)^2 = 0 \]
Thus, the x-intercept is:
\[ x = 3 \]
Verify by substituting back into the original equation. The correct answer is \( x = 3 \).
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