A cannonball fired from a cannon will follow the path of the parabola that is the graph of y = y(x), where y = -16(1 + s ) + + sx feet. Here s is the slope of inclination of the cannon barrel, v, is the initial velocity in feet per second, and the variable distance downrange in feet. Suppose that a cannon is elevated with a slope of 0.5 (corresponding to an angle of inclination of about 27 degrees) and the cannonball is given an initial velocity of 230 feet per second. How far will the cannonball travel? ft Need Help? Read iI

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Maximization

Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.