Solve f(x) = 0 using the iteration Xn+ 1 = Xn-cf(xn), which differs slightly from Newton's method. (Enter your answers as a comma- separated list.) f(x) = x² - 25, with x = 0 X = Find a c that allows the sequence to converge and a c that fails to converge, with the exception of c = 0. converges fails to converge C = C =

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Author:Erwin Kreyszig
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Solve f(x) = 0 using the iteration Xn+ 1 = Xn-cf(xn), which differs slightly from Newton's method. (Enter your answers as a comma-
separated list.)
f(x) = x² - 25, with x = 0
X =
Find a c that allows the sequence to converge and a c that fails to converge, with the exception of c = 0.
converges
fails to converge
C =
C =
Transcribed Image Text:Solve f(x) = 0 using the iteration Xn+ 1 = Xn-cf(xn), which differs slightly from Newton's method. (Enter your answers as a comma- separated list.) f(x) = x² - 25, with x = 0 X = Find a c that allows the sequence to converge and a c that fails to converge, with the exception of c = 0. converges fails to converge C = C =
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