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Use Newton's method to find the zeros of f(x) = 3x - 3x using the given starting values in (a) through (c). gin (0.5) 2 (a) xo = 0.9 and Xxo = 1.1, lying in 0, A. For Xo = 0.9 and xo = 1.1, Newton's method does not converge. The values of x; alternate between 0.9 and 1.1 as i increases. B. For Xo = 0 9 and x = 1.1, x 1 as i gets large. (b) x = 0.23 and x = -0.5, lying in √21 √21 7 O A. x = 0.23 and xo = -0.5, Newton's method does not converge. The values of x, alternate between 0.23 and -0.5 as i increases. OB. For x = 0 23 and x = -0.5, xa as i gets large.

Use Newton's method to find the zeros of f(x) = 3x - 3x using the given starting values in (a) through (c). gin (0.5) 2 (a) xo = 0.9 and Xxo = 1.1, lying in 0, A. For Xo = 0.9 and xo = 1.1, Newton's method does not converge. The values of x; alternate between 0.9 and 1.1 as i increases. B. For Xo = 0 9 and x = 1.1, x 1 as i gets large. (b) x = 0.23 and x = -0.5, lying in √21 √21 7 O A. x = 0.23 and xo = -0.5, Newton's method does not converge. The values of x, alternate between 0.23 and -0.5 as i increases. OB. For x = 0 23 and x = -0.5, xa as i gets large.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use Newton's method to find the zeros of f(x) = 3x4 - 3x² using the given starting values in (a) through (c). (a) xo = 0.9 and x = 1.1, lying in 0, 2 A. For Xo = 0.9 and xo = 1.1, Newton's method does not converge. The values of x; alternate between 0.9 and 1.1 as i increases. B. For Xo = 0.9 and x = 1.1, X₁→ 1 as i gets large. (b) x = 0.23 and x = -0.5, lying in √21 √21 ( ) 7 7 O A. Xo = 0.23 and xo = -0.5, Newton's method does not converge. The values of x; alternate between 0.23 and -0.5 as i increases B. For x = 0.23 and x = -0.5, x₁→ as i gets large.
Transcribed Image Text:Use Newton's method to find the zeros of f(x) = 3x4 - 3x² using the given starting values in (a) through (c). (a) xo = 0.9 and x = 1.1, lying in 0, 2 A. For Xo = 0.9 and xo = 1.1, Newton's method does not converge. The values of x; alternate between 0.9 and 1.1 as i increases. B. For Xo = 0.9 and x = 1.1, X₁→ 1 as i gets large. (b) x = 0.23 and x = -0.5, lying in √21 √21 ( ) 7 7 O A. Xo = 0.23 and xo = -0.5, Newton's method does not converge. The values of x; alternate between 0.23 and -0.5 as i increases B. For x = 0.23 and x = -0.5, x₁→ as i gets large.
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