Solve for Ic of Figure 42.12 VIcRcRsVc =6 VVCE B= 80Iz= 40 µAReference. Boylestad, R. & Nashehky, L (2013)Electronic devices and crcuit theory |1 1th od.. UpperSoddle River, New Jersey: Peason EducotionFigure 42O 4 uA3.2 uA03.2 mA04 mA Solve the beta (B) of Figure 611.VCT18VR233.9kQR1680kaVc = 8VFigure 611O 212O 328O 200O239

In this we will find collector current.. Note:- as per our guidelines...I will answer 1st…

Solve for Ic of Figure 42. 12 V Rc Rg Vc =6V VCE B= 80 Is= 40 HA Reference: Boylestad, R. & Nashehky, L (2013) Electronic devices and circuit thooey |1 1th ed.J. Upper Soddle River, New Jersey: Peason Educoioh Figure 42 O 4 uA 3.2 uA O 3.2 mA O 4 mA

Solve for Ic of Figure 42. 12 V Rc Rg Vc =6V VCE B= 80 Is= 40 HA Reference: Boylestad, R. & Nashehky, L (2013) Electronic devices and circuit thooey |1 1th ed.J. Upper Soddle River, New Jersey: Peason Educoioh Figure 42 O 4 uA 3.2 uA O 3.2 mA O 4 mA

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

Solve for Ic of Figure 42.
12 V
Ic
Rc
Rs
Vc =6 V
VCE B= 80
Iz= 40 µA
Reference. Boylestad, R. & Nashehky, L (2013)
Electronic devices and crcuit theory |1 1th od.. Upper
Soddle River, New Jersey: Peason Educotion
Figure 42
O 4 uA
3.2 uA
03.2 mA
04 mA

Solve the beta (B) of Figure 611.
VC
T18V
R2
33.9kQ
R1
680ka
Vc = 8V
Figure 611
O 212
O 328
O 200
O239

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