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Solve and choose the correct answer from the following options, the initial value problem dI + 12I = 72, dt I(0) = 0 where I is a function of t. I(t) = 18 + 6e-3t I(t) = -6 – 6e-3t I(t) = -6+ 6e¬3t I(t) = 6(1 – e I(t) -18+ 6e¬3t

Solve and choose the correct answer from the following options, the initial value problem dI + 12I = 72, dt I(0) = 0 where I is a function of t. I(t) = 18 + 6e-3t I(t) = -6 – 6e-3t I(t) = -6+ 6e¬3t I(t) = 6(1 – e I(t) -18+ 6e¬3t

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Solve and choose the correct answer from the following options, the initial value problem dI + 12I = 72, dt I(0) = 0 where I is a function of t. I(t) = 18 + 6e-3t I(t) = -6 – 6e-3t I(t) = –6+ 6e -3t I(t) = 6(1 – e-3*) I(t) = –18 + 6e-3t
Transcribed Image Text:Solve and choose the correct answer from the following options, the initial value problem dI + 12I = 72, dt I(0) = 0 where I is a function of t. I(t) = 18 + 6e-3t I(t) = -6 – 6e-3t I(t) = –6+ 6e -3t I(t) = 6(1 – e-3*) I(t) = –18 + 6e-3t
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