1. A particle travels in space according to the function: 7 = 2tî + (5t² - t)ĵ + 3t²k and its velocity is: = 2 + (10t - 1)j + 6tk a. At t = 2, what is the position of the particle? b. At t = 2, what is the velocity of the particle? c. At t = 2, what is the cross product between the velocity and the position? d. At t = 2, what is the dot product between the velocity and the position?

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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デジタル形式で段階的に解決
SOLVE STEP BY STEP IN DIGITAL FORMAT
1. A particle travels in space according to the function:
* = 2tî + (5t²-t)j + 3t² k
and its velocity is:
= 21+ (10t - 1)ĵ + 6tk
a. At t = 2, what is the position of the particle?
ありがとう!!
b. At t = 2, what is the velocity of the particle?
c. At t = 2, what is the cross product between the velocity and the position?
d. At t = 2, what is the dot product between the velocity and the position?
-
Transcribed Image Text:デジタル形式で段階的に解決 SOLVE STEP BY STEP IN DIGITAL FORMAT 1. A particle travels in space according to the function: * = 2tî + (5t²-t)j + 3t² k and its velocity is: = 21+ (10t - 1)ĵ + 6tk a. At t = 2, what is the position of the particle? ありがとう!! b. At t = 2, what is the velocity of the particle? c. At t = 2, what is the cross product between the velocity and the position? d. At t = 2, what is the dot product between the velocity and the position? -
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