Consider the two ODEs dy dx dy dx +y=0 + y² = 0 equil eq.2 (a) How are the two equations different in structure? (b) Show that, for any constant C, the function Ce is always a solution of 1, while Ca-¹ is a solution of 2 only when C = 0 or 1. (c) Show that, for any linear equation of the form dy dx eq:3 if z(x) is a solution, then, for any constant C, the function Cz(x) is also a solution. Hint: Plug Cz(x) into 3. + P(x)y = 0,