?? CHEM 103 - Homework 12NameSolutions & Colligative Properties1. The vapor pressure of water at 20°C is 17.5 torr. What is the vapor pressure of water over asolution containing 300. g C6H12O6 and 455 g of water at 20°C?Lab Section2. Calculate the freezing point of a solution made from 32.7 g of propane, C3H8, dissolved in137.0 g of benzene, C6H6. The freezing point of benzene is 5.50°C and its Kf is 5.12°C/m.3. Calculate the boiling point of a solution made from 227 g of MgCl2 dissolved in 700. g ofwater. What is the boiling point of the solution? Kb = 0.512°C/m.4. Calculate the concentration of nitrogen gas in a 1.00 L container exerting a partial pressure of572 mm Hg at room temperature. Henry's law constant for nitrogen at 25°C is 6.8 x 10-4mol/L'atm. (Solve using the information given and factor labelling)W

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Solutions & Colligative Properties 1. The vapor pressure of water at 20°C is 17.5 torr. What is the vapor pressure of water over a solution containing 300. g C6H12O6 and 455 g of water at 20°C? Lab Section

Solutions & Colligative Properties 1. The vapor pressure of water at 20°C is 17.5 torr. What is the vapor pressure of water over a solution containing 300. g C6H12O6 and 455 g of water at 20°C? Lab Section

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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In this particular problem, draw all possible resonance structures on your notebook. Based on your structures, draw the resonance hybrid indicating the partial charges using formal charges. Interactive 3D display mode CH3 Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars, including charges where needed. The single bond is active by default.
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N goNSU | Northeastern State Univ x * OWLV2 | Online teaching and lea X b My Questions | bartleby x + Content A east.cengagenow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator=assignment-take Chapter 6 Homework - EOC [References] 1 pt Calculate the internal energy change for each of the following. Question 1 Question 2 1 pt a. One hundred (100.) joules of work is required to compress a gas. At the same time, the gas releases 43 J of heat. Internal energy change = J Question 3 1 pt Question 4 O 1 pt b. A piston is compressed from a volume of 8.70 L to 4.05 L against a constant pressure of 2.95 atm. In the process, there is a heat gain by the system of 329 J. Question 5 O 1 pt Internal energy change = J O 1 pt c. A piston expands against 1.10 atm of pressure from 20.1 L to 35.2 L. In the process, 1212 J of heat is absorbed. Question 6 Question 7 O 1 pt Internal energy change = J Question 8 1 pt Submit Answer Try Another Version 2 item attempts remaining Question 9 O 1 pt Question…
AutoSave Module 4; Lewis Structures of Covalent Compounds - Saved to this PC P Searc Off File Home Insert Draw Design Layout References Mailings Review View Help Grammarly Times New Roma v 12 A A Aa v AaBbCcI AaBbCcI Aa Paste в IU ab х, х* А A I Normal I No Spac.. Hea Clipboard Font Paragraph 4..| 5 9... |·· 10. . |. 11. ..| 12. . | 13... 14. 15. * The speaker uses the term "lone electron pair" instead of non-bonding electron pair. It is the same thing. **Number VESPR Groups is equal to the number of atoms bonded to the central atom plus the mumber oaf ncn-bonding pairs. Draw the Lenis structure Name the shape. ihoning the correct :kape. LUse element symbols, dots for ncn- bonding electron pairs and dashes for banded electrons. BeCl, со. HCN BF, CH.O so, CH, NH, Number of VESPR
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