solution of 0.138 M aspartic acid, the charge neutral form of the amino acid, is titrated with 0.0460 M NaOH . The p?a values for aspartic acid are 1.990 , 3.900 , and 10.002 , corresponding to the α-carboxylic acid group, the β-carboxylic
solution of 0.138 M aspartic acid, the charge neutral form of the amino acid, is titrated with 0.0460 M NaOH . The p?a values for aspartic acid are 1.990 , 3.900 , and 10.002 , corresponding to the α-carboxylic acid group, the β-carboxylic
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 105QRT: Apatite, Ca5(PO4)3OH, is the mineral in teeth.
On a chemical basis explain why drinking milk...
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A solution of 0.138 M aspartic acid, the charge neutral form of the amino acid, is titrated with 0.0460 M NaOH . The p?a values for aspartic acid are 1.990 , 3.900 , and 10.002 , corresponding to the α-
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