Sodium oxalate, Na2C2 04, in solution is oxidized to CO2 (g) by MnO, which is reduced to Mn2+. A 50.1 – mL volume of a solution of MnO, is required to titrate a 0.337 - g sample of sodium oxalate. This solution of Mno, is then used to analyze uranium-containing samples. A 4.61 - g sample of a uranium-containing material requires 32.5 mL of the solution for titration. The oxidation of the uranium can be represented by the change UO²+ → UO*. - |
Sodium oxalate, Na2C2 04, in solution is oxidized to CO2 (g) by MnO, which is reduced to Mn2+. A 50.1 – mL volume of a solution of MnO, is required to titrate a 0.337 - g sample of sodium oxalate. This solution of Mno, is then used to analyze uranium-containing samples. A 4.61 - g sample of a uranium-containing material requires 32.5 mL of the solution for titration. The oxidation of the uranium can be represented by the change UO²+ → UO*. - |
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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a) Calculate the percentage of uranium in the sample.

Transcribed Image Text:<Problem Set # 10 (Ch 19) Attempt 1
Exercise 19.131
Sodium oxalate, Na2C2 O4, in solution is oxidized
to CO2 (g) by MnO, which is reduced to Mn2+.
A 50.1 – mL volume of a solution of MnO, is
required to titrate a 0.337
oxalate. This solution of Mno, is then used to
analyze uranium-containing samples. A 4.61 - g
sample of a uranium-containing material requires
32.5 mL of the solution for titration. The oxidation
of the uranium can be represented by the change
UO²+ → UO?+.
g sample of sodium
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