4. Suppose you have a mixture that weighs 6.00 g. In the mixture you 2.50 g of iron and 3.50 g of sulfur. What are the mass percentages of iron and sulfur in the mixture?
4. Suppose you have a mixture that weighs 6.00 g. In the mixture you 2.50 g of iron and 3.50 g of sulfur. What are the mass percentages of iron and sulfur in the mixture?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem 4: Mass Percentage Calculation**
Suppose you have a mixture that weighs 6.00 g. In the mixture, you have 2.50 g of iron and 3.50 g of sulfur. What are the mass percentages of iron and sulfur in the mixture?
---
**Solution:**
To find the mass percentages of each component in the mixture, use the formula for mass percentage:
\[
\text{Mass percentage of component} = \left(\frac{\text{Mass of the component}}{\text{Total mass of the mixture}}\right) \times 100
\]
**Mass percentage of iron:**
\[
\text{Mass percentage of iron} = \left(\frac{2.50 \, \text{g}}{6.00 \, \text{g}}\right) \times 100 \approx 41.67\%
\]
**Mass percentage of sulfur:**
\[
\text{Mass percentage of sulfur} = \left(\frac{3.50 \, \text{g}}{6.00 \, \text{g}}\right) \times 100 \approx 58.33\%
\]
Therefore, the mass percentages are approximately 41.67% iron and 58.33% sulfur.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8466d554-389f-4c93-a2cb-098ffb2eb61b%2F42b9afbc-6a03-42ef-94a9-338823f6e5c4%2Fqs5cvuh_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 4: Mass Percentage Calculation**
Suppose you have a mixture that weighs 6.00 g. In the mixture, you have 2.50 g of iron and 3.50 g of sulfur. What are the mass percentages of iron and sulfur in the mixture?
---
**Solution:**
To find the mass percentages of each component in the mixture, use the formula for mass percentage:
\[
\text{Mass percentage of component} = \left(\frac{\text{Mass of the component}}{\text{Total mass of the mixture}}\right) \times 100
\]
**Mass percentage of iron:**
\[
\text{Mass percentage of iron} = \left(\frac{2.50 \, \text{g}}{6.00 \, \text{g}}\right) \times 100 \approx 41.67\%
\]
**Mass percentage of sulfur:**
\[
\text{Mass percentage of sulfur} = \left(\frac{3.50 \, \text{g}}{6.00 \, \text{g}}\right) \times 100 \approx 58.33\%
\]
Therefore, the mass percentages are approximately 41.67% iron and 58.33% sulfur.
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