**Problem 4: Mass Percentage Calculation**Suppose you have a mixture that weighs 6.00 g. In the mixture, you have 2.50 g of iron and 3.50 g of sulfur. What are the mass percentages of iron and sulfur in the mixture?---**Solution:**To find the mass percentages of each component in the mixture, use the formula for mass percentage:\[\text{Mass percentage of component} = \left(\frac{\text{Mass of the component}}{\text{Total mass of the mixture}}\right) \times 100\]**Mass percentage of iron:**\[\text{Mass percentage of iron} = \left(\frac{2.50 \, \text{g}}{6.00 \, \text{g}}\right) \times 100 \approx 41.67\%\]**Mass percentage of sulfur:**\[\text{Mass percentage of sulfur} = \left(\frac{3.50 \, \text{g}}{6.00 \, \text{g}}\right) \times 100 \approx 58.33\%\]Therefore, the mass percentages are approximately 41.67% iron and 58.33% sulfur.

The total weight of mixture is 6.00 g. The mass of iron and sulfur present in mixture is 2.50 g and…

Answered: 4. Suppose you have a mixture that…

4. Suppose you have a mixture that weighs 6.00 g. In the mixture you 2.50 g of iron and 3.50 g of sulfur. What are the mass percentages of iron and sulfur in the mixture?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Stoichiometry

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Question

**Problem 4: Mass Percentage Calculation**

Suppose you have a mixture that weighs 6.00 g. In the mixture, you have 2.50 g of iron and 3.50 g of sulfur. What are the mass percentages of iron and sulfur in the mixture?

---

**Solution:**

To find the mass percentages of each component in the mixture, use the formula for mass percentage:

\[
\text{Mass percentage of component} = \left(\frac{\text{Mass of the component}}{\text{Total mass of the mixture}}\right) \times 100
\]

**Mass percentage of iron:**

\[
\text{Mass percentage of iron} = \left(\frac{2.50 \, \text{g}}{6.00 \, \text{g}}\right) \times 100 \approx 41.67\%
\]

**Mass percentage of sulfur:**

\[
\text{Mass percentage of sulfur} = \left(\frac{3.50 \, \text{g}}{6.00 \, \text{g}}\right) \times 100 \approx 58.33\%
\]

Therefore, the mass percentages are approximately 41.67% iron and 58.33% sulfur.

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