**Calculate the Mass in Grams of Methanol**Given:- **Number of molecules:** \(3.65 \times 10^{24}\) molecules of methanol.- **Chemical formula for methanol:** \(CH_4O\).**Objective:**Calculate the mass in grams.**Mass:**\[ \underline{\qquad\qquad\qquad} \text{ g} \] **Explanation:**To calculate the mass:1. **Determine molar mass** of methanol (\(CH_4O\)): - Carbon (C): 12.01 g/mol - Hydrogen (H): 1.01 g/mol × 4 = 4.04 g/mol - Oxygen (O): 16.00 g/mol - Total molar mass of \(CH_4O\): 12.01 + 4.04 + 16.00 = 32.05 g/mol2. **Use Avogadro's number** (\(6.022 \times 10^{23}\)) to convert molecules to moles.3. **Mass calculation:** \[ \text{Moles of methanol} = \frac{3.65 \times 10^{24}}{6.022 \times 10^{23}} = \text{approximately 6.06 moles} \] \[ \text{Mass} = \text{moles} \times \text{molar mass} = 6.06 \times 32.05 = \text{approximately 194.4 g} \]Insert the calculated mass into the provided space.

Given, Number of molecules of methanol (CH4O) = 3.65 × 1024 molecules Mass (in grams) of 3.65 × 1024 molecules of methanol (CH4O) = ? Note: Molar mass of methanol (CH4O) = (12 + 4×1 + 16) g/mol = 32 g/mol 1 mole of methanol contains 6.022 × 1023 molecules of methanol. Avogadro's number = 6.022 × 1023 Calculating mass (in grams) of 3.65 × 1024 molecules of methanol (CH4O):Conclusion: So, the mass (in grams) of 3.65 × 1024 molecules of methanol (CH4O) is 194 grams. Answer: mass: 194 g