Sodium ions (Na+) move at 0.858 m/s through a bloodstream in the arm of a person standing near a large magnet. The magnetic field has a strength of 0.254 T and makes an angle of 57.0° with the motion of the sodium ions. The arm contains 115 cm³ of blood with a concentration of 4.00 x 1020 Na+ ions per cubic centimeter. If no other ions were present in the arm, what would be the magnetic force on the arm? N

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

Sodium ions (Na⁺) move at 0.858 m/s through a bloodstream in the arm of a person standing near a large magnet. The magnetic field has a strength of 0.254 T and makes an angle of 57.0° with the motion of the sodium ions. The arm contains 115 cm³ of blood with a concentration of 4.00 x 10²⁰ Na⁺ ions per cubic centimeter. If no other ions were present in the arm, what would be the magnetic force on the arm?

\[ \text{Magnetic Force} = \_ \_ \_ \_ \_ \_ \ \text{N} \]
Transcribed Image Text:**Problem Statement:** Sodium ions (Na⁺) move at 0.858 m/s through a bloodstream in the arm of a person standing near a large magnet. The magnetic field has a strength of 0.254 T and makes an angle of 57.0° with the motion of the sodium ions. The arm contains 115 cm³ of blood with a concentration of 4.00 x 10²⁰ Na⁺ ions per cubic centimeter. If no other ions were present in the arm, what would be the magnetic force on the arm? \[ \text{Magnetic Force} = \_ \_ \_ \_ \_ \_ \ \text{N} \]
Expert Solution
Step 1

Given data:

The velocity, v=0.858 m/s

The angleθ=57.0° 

The magnetic field, B=0.254 T

The total number of sodium ions, n=115 cm3×4.00×1020 /cm3

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