### Understanding Magnetic Force on a Charged ParticleIn an experiment, a particle with a mass of \(6.80 \times 10^{-27} \, \text{kg}\) enters a uniform magnetic field with a strength of \(0.350 \, \text{T}\). The magnetic field is directed out of the page, as indicated by blue dots representing the field lines. The particle travels in a semi-circular path with a diameter of \(64.0 \, \text{cm}\).#### Problem:If the particle is moving with a speed of \(5.40 \times 10^6 \, \text{m/s}\), determine the magnitude and sign of the particle's charge.#### Options:- \(+\ 1.64 \times 10^{-19} \, \text{C}\)- \(-\ 1.31 \times 10^{-18} \, \text{C}\)- \(+\ 8.85 \times 10^{-13} \, \text{C}\)- \(+\ 1.31 \times 10^{-18} \, \text{C}\)- Not enough information- \(-\ 8.85 \times 10^{-13} \, \text{C}\)- \(+\ 6.10 \times 10^{-18} \, \text{C}\)- \(-\ 6.10 \times 10^{-18} \, \text{C}\)- \(+\ 3.28 \times 10^{-19} \, \text{C}\)- \(-\ 1.64 \times 10^{-19} \, \text{C}\)- \(-\ 3.28 \times 10^{-19} \, \text{C}\)#### Diagram Explanation:The diagram shows a top view of the experimental setup. The magnetic field is uniform and coming out of the page. As the particle enters this field, it curves in a path defining a semi-circle, due to the Lorentz force acting perpendicular to its initial velocity. The semi-circle is delineated by a dashed line with a diameter noted as \(64.0 \, \text{cm}\).To find the charge, use the formula for the magnetic force and centripetal force balance:\[ F_{\text{magnetic}} = F_{\text{centripetal}}

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Answered: 64.0 cm -➜ B In an experiment, a…

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