Sodium hydride is a very strong base. In this reaction, one equivalent of sodium hydride is reacting with the thioalcohol shown with a 1-to-1 stoichiometry. Predict the products of this reaction (include both conjugate acid and base), draw the mechanistic arrows and explain why this product is formed. H Na :H .S: 1 equivalent エーの: エ-O:
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
![Sodium hydride is a very strong base. In this reaction, one equivalent of sodium hydride is reacting with the thioalcohol shown with a 1-to-1 stoichiometry. Predict the products of this reaction (include both conjugate acid and base), draw the mechanistic arrows and explain why this product is formed.
**Diagram Explanation:**
- The reactant is a thioalcohol containing an OH group and an SH group.
- Sodium hydride (Na⁺ ⁻H) is shown as the other reactant, with one equivalent indicated.
- An arrow points from the reactants toward the products, illustrating the reaction pathway.
To complete the reaction:
1. Identify the acidic hydrogen in the thioalcohol that will be deprotonated by hydride.
2. Show the flow of electrons from the hydride ion attacking the hydrogen atom, leading to the formation of H₂ gas and a thiolate ion.
3. The product side should include sodium thiolate (where the sulfur anion pairs with the sodium cation) and hydrogen gas formed.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F89b818ed-2b56-4ed1-ae0c-ef21eaac3b75%2F031a3cf8-194e-41ed-829a-db8f7efded62%2Fi3dlfw_processed.png&w=3840&q=75)
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