Draw the structure of the product of the reaction between the compound shown below and BF3. CH3CH₂OH • You do not have to consider stereochemistry. You do not have explicitly draw H atoms. • If the reaction involves proton transfer, draw the products in separate sketchers. • If the reaction is a Lewis acid-base reaction, draw the product in one sketcher only. 7-8 3 9.85 OOO. SIF Base + Acid H₂COH изсизон ChemDoodle remove 226 22 4 ·000- F ChemDoodle Conj. base Com). *182 GRA 0. 000. SIF H₂co ChemDoodle Conjacid ✔399-8 H▾ 000 ChemDoodleⓇ
Draw the structure of the product of the reaction between the compound shown below and BF3. CH3CH₂OH • You do not have to consider stereochemistry. You do not have explicitly draw H atoms. • If the reaction involves proton transfer, draw the products in separate sketchers. • If the reaction is a Lewis acid-base reaction, draw the product in one sketcher only. 7-8 3 9.85 OOO. SIF Base + Acid H₂COH изсизон ChemDoodle remove 226 22 4 ·000- F ChemDoodle Conj. base Com). *182 GRA 0. 000. SIF H₂co ChemDoodle Conjacid ✔399-8 H▾ 000 ChemDoodleⓇ
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Understanding Acid-Base Reactions: A Detailed Example
**Problem Statement**
Draw the structure of the product of the reaction between the compound shown below and \( BF_3 \).
**Given Compound:**
\[ CH_3CH_2OH \]
### Guidelines
- You do not have to consider stereochemistry.
- You do not have to explicitly draw H atoms.
- If the reaction involves proton transfer, draw the products in separate sketchers.
- If the reaction is a Lewis acid-base reaction, draw the product in one sketcher only.
### Reaction Breakdown
1. **Identifying the Acid and Base**
The first image shows the given compound \( CH_3CH_2OH \) (ethanol) labeled as "Acid" and the Lewis structure of \( BF_3 \) labeled as "Base".
**Ethanol (Acid)**:
\[
H_3C-CH_2-OH
\]
**Boron Trifluoride (Base)**:
\[
BF_3 \quad (\text{with Lewis structure})
\]
The \( BF_3 \) molecule can accept an electron pair, acting as a Lewis acid in this context since it has an empty p-orbital.
2. **Reaction and Products**
The second and third images depict the products of the reaction, labeled "Conjugate Base" and "Conjugate Acid".
**Conjugate Base**:
The ethanol after losing a proton (H+):
\[
H_3C-CH_2-O^-
\]
**Conjugate Acid**:
The \( BF_3 \) after bonding with the hydroxyl group:
\[
H \quad (\text{attached to} \quad BF_3)
\]
Unfortunately, the specific placement of \( BF_3 \) is not clearly shown in the annotation.
### Final Visualization
The products should be visualized as individual entities:
1. **Ethanol Acid Product:**
\[
CH_3CH_2O^- \quad (\text{Conjugate Base})
\]
2. **BF3-based Product:**
\[
BF_3H \quad (\text{Conjugate Acid, specifically where the \( BF_3 \) attaches to an oxygen site})
\]
This visualization helps in understanding the](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b49abb7-22b1-43f4-8ea9-ededd2a6e7a5%2Fa123fd40-71d7-4a7f-ad03-c1fed010ac45%2F2e3hfg8_processed.png&w=3840&q=75)
Transcribed Image Text:### Understanding Acid-Base Reactions: A Detailed Example
**Problem Statement**
Draw the structure of the product of the reaction between the compound shown below and \( BF_3 \).
**Given Compound:**
\[ CH_3CH_2OH \]
### Guidelines
- You do not have to consider stereochemistry.
- You do not have to explicitly draw H atoms.
- If the reaction involves proton transfer, draw the products in separate sketchers.
- If the reaction is a Lewis acid-base reaction, draw the product in one sketcher only.
### Reaction Breakdown
1. **Identifying the Acid and Base**
The first image shows the given compound \( CH_3CH_2OH \) (ethanol) labeled as "Acid" and the Lewis structure of \( BF_3 \) labeled as "Base".
**Ethanol (Acid)**:
\[
H_3C-CH_2-OH
\]
**Boron Trifluoride (Base)**:
\[
BF_3 \quad (\text{with Lewis structure})
\]
The \( BF_3 \) molecule can accept an electron pair, acting as a Lewis acid in this context since it has an empty p-orbital.
2. **Reaction and Products**
The second and third images depict the products of the reaction, labeled "Conjugate Base" and "Conjugate Acid".
**Conjugate Base**:
The ethanol after losing a proton (H+):
\[
H_3C-CH_2-O^-
\]
**Conjugate Acid**:
The \( BF_3 \) after bonding with the hydroxyl group:
\[
H \quad (\text{attached to} \quad BF_3)
\]
Unfortunately, the specific placement of \( BF_3 \) is not clearly shown in the annotation.
### Final Visualization
The products should be visualized as individual entities:
1. **Ethanol Acid Product:**
\[
CH_3CH_2O^- \quad (\text{Conjugate Base})
\]
2. **BF3-based Product:**
\[
BF_3H \quad (\text{Conjugate Acid, specifically where the \( BF_3 \) attaches to an oxygen site})
\]
This visualization helps in understanding the
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So, in this lewis acid-base reaction, do we need to draw lone pairs or not? Why or why not? Thank you.
Transcribed Image Text:H₂
H3C-
-OH F
+
LL
F
LL
H3C-
H₂
-CO
F-B
HO
LL
Solution
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