Smoking Survey: National statistics show that 23% of men smoke and 18.5% of women do. A random sample of 131 men indicated that 41 were smokers, and of 120 women surveyed, 24 indicated that they smoked.Part: 0/2Part 1 of 2Construct a 94% confidence interval for the true difference in proportions of male and female smokers. Use \( \hat{p}_1 \) for the proportion of men who smoke. Round your answers to three decimal places.\[ < \hat{p}_1 - \hat{p}_2 < \]The image includes a button interface with buttons labeled from 1 to 9 (with button 9 being highlighted), and language selection set to Español.

given data n1 = 131 x1 = 41p^1 = x1n1 = 41131 = 0.3130 n2 = 120 x2 = 24p^2 = x2n2 = 24120 =…

Answered: Smoking Survey National statistics show…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Please show solving steps and if possible what excel functions are used to get these answers
According to a report on consumer fraud and identity theft, 20% of all complaints for a year were for identity theft. In that year, Oregon had 714 complaints of identity theft out of 3449 consumer complaints. Does this data provide enough evidence to show that Oregon had a higher proportion of identity theft than 20%? Test at the 5% level. State the hypotheses. Họ: P ?v Ha: P ? Calculate the test statistic. Round to four decimal places. Calculate the standardized test statistic. Round to three decimal places. z = Find the p-value. Round to four decimal places. p-value = State your decision. O Since the p-value is less than .05, reject Ho. O Since the p-value is greater than .05, fail to reject Ho. O Since the p-value is greater than .05, reject Ho- O Since the p-value is less than .05, fail to reject Ho- Interpret the results. O At the 5% level of significance, there is not enough evidence to show that the proportion of complaints due to identity theft in Oregon is less than 20%. O At…
You are interested in finding a 98% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 11 randomly selected non-residential college students. Round answers to 3 decimal places where possible. 18 18 27 17 15 7 11 15 9 12 19 a. With 98% confidence the population mean commute for non-residential college students is between _____ and____miles. b. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About (____) percent of these confidence intervals will contain the true population mean number of commute miles and about(_____) percent will not contain the true population mean number of commute miles.
Files Font Paragraph rStyles Voice Editor Reuse Fi BIRTH WEIGHT OF GIRLS: Use the summary statistics given: n 205, = 30.4, s = 7.1 Use a 95% confidence level and construct a confidence interval. (MUST SHOW YOUR WORK to get full credit) 19. earch 耳 | 99+
A psychiatrist is interested in finding a 98% confidence interval for the tics per hour exhibited by children with Tourette syndrome. The data below show the tics in an observed hour for 11 randomly selected children with Tourette syndrome. Round your decimal 3 places. 1,12,11,6,10,1,4,7,8,1,9 With 98% confidence the population mean number of tics per hour that children with Tourette syndrome exhibit is between ____ and ____ If many groups of 11 randomly selected children with Tourette syndrome are observed, then a different confidence interval would be produced from each group. About ____ percent of these confidence intervals will contain the true population mean number of tics per hour and about ____ percent will not contain the true population mean number of tics per hour.
Out of 400 people sampled, 224 had children under the age of 18. Based on this, construct a 90% confidence interval for the true population proportion of people with children under the age of 18.Give your answers as decimals, to three places.________< p <________
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We wish to estimate what percent of adult residents in a certain county are parents. Out of 400 adult residents sampled, 356 had kids. Based on this, construct a 95% confidence interval for the proportion, p, of adult residents who are parents in this county.Give your answers as decimals, to three places. ______ < p < _______
Pls help ASAP. Pls show all work. Pls do both of the asked questions pls i BEG.
NEED ANSWER FOR BOTH ASAP BOTH ARE FOR SAME QUESTION
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You are interested in finding a 90% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 13 randomly selected college students. Round answers to 3 decimal places where possible. 7 8 8 0 2 11 6 10 2 0 1 3 1 With 90% confidence the population mean number of days of class that college students miss is between and days.

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