On average, Americans have lived in 2 places by the time they are 18 years old. Is this average less for college students? The 62 randomly selected college students who answered the survey question had lived in an average of 1.99 places by the time they were 18 years old. The standard deviation for the survey group was 0.3. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use t-test for a population mean b. The null and alternative hypotheses would be:

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### Statistical Hypothesis Testing Example

**Scenario:**

On average, Americans have lived in 2 places by the time they are 18 years old. Is this average less for college students? 

To investigate, 62 randomly selected college students who answered the survey question had lived in an average of 1.99 places by the time they were 18 years old. The standard deviation for the survey group was 0.3. We will conclude based on the \( \alpha = 0.10 \) level of significance.

**Procedure:**

a. **Selecting the appropriate test:**
  
   For this study, we should use:
   
   - **t-test for a population mean**

b. **Formulating hypotheses:**
  
   The null and alternative hypotheses would be:

   - \( H_0 \): \( \mu \geq 2 \) (The average number of places for college students is not less than 2)
   
   - \( H_1 \): \( \mu < 2 \) (The average number of places for college students is less than 2)

c. **Calculating the test statistic:**
  
   The formula for the t-test statistic is:

   \[
   t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}}
   \]

   where:
   - \( \bar{x} \) = sample mean = 1.99
   - \( \mu_0 \) = population mean = 2
   - \( s \) = standard deviation = 0.3
   - \( n \) = sample size = 62

   Substitute these values into the formula to calculate the t statistic:

   \[
   t = \frac{1.99 - 2}{0.3 / \sqrt{62}}
   \]

   (please show your answer to 3 decimal places.)

d. **Finding the p-value:**
  
   The p-value is found using the t distribution table or statistical software. 

   - (Please show your answer to 4 decimal places.)

By comparing the p-value to the alpha level, we can determine whether to reject or fail to reject the null hypothesis.

**Note:**

The "Select an answer" dropdowns and blank boxes are meant for students to fill in their answers during the exercise. Statistical software or a t-distribution table is typically used to calculate the exact values
Transcribed Image Text:### Statistical Hypothesis Testing Example **Scenario:** On average, Americans have lived in 2 places by the time they are 18 years old. Is this average less for college students? To investigate, 62 randomly selected college students who answered the survey question had lived in an average of 1.99 places by the time they were 18 years old. The standard deviation for the survey group was 0.3. We will conclude based on the \( \alpha = 0.10 \) level of significance. **Procedure:** a. **Selecting the appropriate test:** For this study, we should use: - **t-test for a population mean** b. **Formulating hypotheses:** The null and alternative hypotheses would be: - \( H_0 \): \( \mu \geq 2 \) (The average number of places for college students is not less than 2) - \( H_1 \): \( \mu < 2 \) (The average number of places for college students is less than 2) c. **Calculating the test statistic:** The formula for the t-test statistic is: \[ t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}} \] where: - \( \bar{x} \) = sample mean = 1.99 - \( \mu_0 \) = population mean = 2 - \( s \) = standard deviation = 0.3 - \( n \) = sample size = 62 Substitute these values into the formula to calculate the t statistic: \[ t = \frac{1.99 - 2}{0.3 / \sqrt{62}} \] (please show your answer to 3 decimal places.) d. **Finding the p-value:** The p-value is found using the t distribution table or statistical software. - (Please show your answer to 4 decimal places.) By comparing the p-value to the alpha level, we can determine whether to reject or fail to reject the null hypothesis. **Note:** The "Select an answer" dropdowns and blank boxes are meant for students to fill in their answers during the exercise. Statistical software or a t-distribution table is typically used to calculate the exact values
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