SITUATION 4:Using the provisions of NSCP Section411.3 the allowable shear stress ofconcrete parallel to the longer directionis 0.816 MPa.A 600mm x 400mm reinforcedconcrete column is reinforced with 8-28mm diameter bars that are equallydistributed around its perimeter. Tiesare 12 mm diameter while concretecover from edge of ties to face ofmember is 40mm.fe = 27.6 MPa, fy = 415 MPa11. Which of the following gives theultimate factored shear force, Vu in theshorter direction of column if thenominal strength to be provided by theties is 375 kN. Use o = 0.75.a. 255.14 kNc. 279.40 kNb. 403.89 kNd. 525.94 kN12. Which of the following gives theultimate factored shear force, Vu in thelonger direction of column if the ties arespaced at every 220 mm. Use o = 0.75.a. 367.348 kNc. 387.348 kNb. 438.67 kNd. 567.35 kN13. Compute for ultimate axial load thatthe section could carry? Use o = 0.65.a. 5233.14 kNC. 4233.74 kNb. 3233.24 kNd. 3930.75 kN

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SITU ION 4: Using the provisions of NSCP Section 411.3 the allowable shear stress of concrete parallel to the longer direction is 0.816 MPa. A 600mm x 400mm reinforced concrete column is reinforced with 8- 28mm diameter bars that are equally distributed around its perimeter. Ties are 12 mm diameter while concrete cover from edge of ties to face of member is 40mm. f.' = 27 6 MPa fy - 415 MPa

SITU ION 4: Using the provisions of NSCP Section 411.3 the allowable shear stress of concrete parallel to the longer direction is 0.816 MPa. A 600mm x 400mm reinforced concrete column is reinforced with 8- 28mm diameter bars that are equally distributed around its perimeter. Ties are 12 mm diameter while concrete cover from edge of ties to face of member is 40mm. f.' = 27 6 MPa fy - 415 MPa

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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