17.33 to 18.67Thus, we can say with 99% confidence that theinterval between 17.33 and 18.67 contains thetrue mean age the population of enteringmathematics majors based on the sample of 25entering mathematics majors.d. Describe the results.R4.ACTIVITYShow your step by step solution.Andrei wants to know if cooperative grouping is an effective strategy in improving the mathematicsperformance of Grade 7 students. Twenty students were included in the experimental group while another 20students were included in the control group. The mean achievement score of the students in the experimentalgroup was 82.5 with a standard deviation of 3 while the mean of the students in the control group was 80 with astandard deviation of 6. The two groups come form normally distributed populations. The confidence leveladopted was 95%.1. What is the estimate of the population mean where the experimental group and control group comesfrom?2. Compute the lower and the upper confidence limits of the experimental and control group.Solutions:a. Point EstimateStepsSolution1. Describe the population parameter ofinterest.The parameter bf nterest is the meanMof

It is given than 20 students were included in experimental group and 20 students were included in…

Answered: SIOW yuui ut Andrei wants to know if…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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On average, adults spend approximately 5 hours per night in NREM (non-rapid eye movement) sleep. A sleep study selects a random sample of adults and gives them each a weighted blanket. They would like to know if using the weighted blanket changes the mean number of hours per night of NREM sleep. We want to test = 5 versus ≠ 5 where = the true mean hours of NREM sleep per night for adults who use a weighted blanket. A 99% confidence interval for the true mean hours of NREM sleep per night for adults who use a weighted blanket is (5.1, 5.8) hours. Based on the confidence interval, what conclusion would you make for a test of these hypotheses? The 99% confidence interval include as a plausible value, so we would H0. We convincing evidence that the true mean hours of NREM sleep per night for adults who use a weighted blanket 5 hours.
Values 2- -2 Group 1 Data Set 1 Example Data by Groups Group 2 Group 3 Values 20- 10- -10- Group 1 Data Set 2 Example Data by Groups Group 2 Group 3
A small business wanted to estimate the mean income from their customers. They took a sample of 256 customers which yielded a sample mean of $71,250 with a standard deviation of $5,800 . What is the 90% confidence interval estimate for the population mean income of their customers.
An insurance company collects data on seat-belt use among drivers in a country. Of 1200drivers 20-29years old,31% said that they buckle up, whereas 385 of 1300 drivers 45-64 years old said that they did. Find a 99% confidence interval for the difference between the proportions of seat-belt users for drivers in the age groups 20-29 years and 45-64 years. Question content area bottom Part 1 Construct a 99% confidence interval. The 99% confidence interval for p1−p2 is from enter your response here to enter your response here. (Round to three decimal places as needed.)
A second-semester junior at a large high school wants to estimate the number of colleges a senior applies to on average before deciding which school they will attend. The junior randomly selects 18 seniors and asks them how many colleges they applied to and records the number. A 99% confidence interval is calculated to estimate the true mean number of colleges seniors at this school apply to before deciding which college to attend. Check all the true statements that apply. Reducing the confidence level will reduce the margin of error. Increasing the sample size will reduce the margin of error. Increasing the sample size will cost this junior too much money. The junior can lower the standard deviation and that would reduce the margin of error. If they decrease the confidence level, then they are decreasing the level of certainty that they have captured the true mean.
We have developed a new drug used to reduce fever and want to test its efficacy. Ten ER patients who are running a fever agree to take the new drug instead of the traditional treatment. Their temperatures are taken before the drug is administered and 30 minutes after taking the drug. The results are recorded in the Excel file below. Use the data to construct and interpret a 99% confidence interval for the mean change in temperatures of patients after taking this drug using Excel. Be sure to include any explanation necessary along with a sentence that explains what the interval means. First Temp Second Temp 100.1 98.9 101.3 99.1 102.1 99.2 102.7 99 101.9 98.7 100.8 98.6 103.1 99.4 102.5 99.2 103.5 100.1 101.7 99.2
Paint used to paint lines on roads must reflect enough light to be clearly visible at night. Researchers have 2 new types of paints they want to test paint type A and paint type B. For each paint type, they tested if there was statistical evidence the average reflectometer reading is greater than 35. To test each type of paint, they used 15 paint samples. Further, suppose the standard deviation is the same for both types of paints. The sample mean for paint type A was 39 and the sample mean for paint type B was 41.5. For both statistical tests, the significance level is set to .05.Which of the following is true? If they fail to reject the null hypothesis for paint type A we can conclude there is statistical evidence the average reflectometer for type A paint is 35. The p-value for the type B paint test is smaller. They rejected the null hypothesis for both paint types. Exactly two of the statements above are true. None are true.
Why are confidence intervals important and what do they mean to a study?
A researcher wants to compare the effectiveness of two different study techniques for a test. The mean test score for the first technique is 75 with a standard deviation of 5, and the mean test score for the second technique is 80 with a standard deviation of 4. The sample size for each group is 20. What is the 95% Confidence Interval for the difference in the mean test scores for the two techniques?
Assume a researcher wants to compare the mean Alanine Aminotransferase (ALT) levels in two populations, individuals who drink alcohol and individuals who do not drink alcohol. The mean ALT levels for the individuals who do not drink alcohol is 32 with a standard deviation of 14, and 37 individuals were in the sample. The mean ALT levels for individuals who drink alcohol is 69 with a standard deviation of 19, and 38 individuals were in the sample. Construct and interpret a 95% confidence interval demonstrating the difference in means for those individuals who drink alcohol when compared to those who do not drink alcohol.
There are many ways to measure the reading ability of children. One frequently used test is the DRP or Degree of Reading Power. The national average score in DRP test is 32. We want to determine if there is sufficient evidence at the 5% level to suggest that the mean score of all third graders in YOUR district is higher than the national mean. The DRP scores for a simple random sample of 41 third graders in that suburban school in YOUR district yielded a mean of 35.2. Assume that the population of DRP scores of third graders in that suburban school district are normally distributed with a population std.dev of 11.
The ACCUPLACER is a college readiness exam. The scores for the math section are normally distributed with a mean of 75 and standard deviation of 8. A college policy is that the bottom 15% of test takers are required to take a remedial math course over the summer. Students who score below what score will have to take the summer course?

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