Since E can be used to determine Q and vice versa, if you know the Ksp of a salt, you can use it to find the cell potential. Imagine a concentration cell in which one half- cell has a silver electrode in a saturated solution of Ag3PO4 and the other half-cell is a silver electrode in a 0.5 M solution of AgNO3. We start with determining the concentration of Ag+ in the saturated solution. The Ksp of silver phosphate is 1.8 x 10-18 What is the solubility of silver phosphate? What is the concentration of Ag+? Now we can use the Nernst equation to find E for our cell: Ag(s) Agaq) (saturated conc. c.) || Ag(aq) (0.5 M) | A A In the Nernst equation, what value will we have for E*? A/ A Now we can use the Nernst equation to find E for our cell: Ag(s) Ag(aq) saturated conc. ) || Ag) (0.5 M)| Ag(s) In the Nernst equation, what value will we have for Eº? A In the Nernst equation, what value will we have for n? A/ Ag(s) Given the concentration you found, what is the value for Q? (If you couldn't solve the first part, use 1.0 x 103 M as the concentration you needed to find so you can solve for Q and continue the problem). A Now solve for E. What is this value? Use 298 K as the temperature and 96485 C/s for F

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Chapter18: Electrochemistry
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Problem 81E: Consider a concentration cell that has both electrodes made of some metal M. Solution A in one...
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Question 4
Since E can be used to determine Q and vice versa, if you know the Ksp of a salt, you
can use it to find the cell potential. Imagine a concentration cell in which one half-
cell has a silver electrode in a saturated solution of Ag3PO4 and the other half-cell is
a silver electrode in a 0.5 M solution of AgNO3.
We start with determining the concentration of Ag+ in the saturated solution. The
Ksp of silver phosphate is 1.8 x 10-18.
What is the solubility of silver phosphate?
What is the concentration of Ag+?
Now we can use the Nernst equation to find E for our cell:
Ag(s) Aga) (saturated conc.
A/
A
In the Nernst equation, what value will we have for E?
A
A
A/
Now we can use the Nernst equation to find E for our cell:
Ag(s) Ag(aq) (saturated conc. .) || Agaq) (0.5 M) | Ag(s)
In the Nernst equation, what value will we have for Eº?
nc.) || Agaq) (0.5 M) |
In the Nernst equation, what value will we have for n?
A
Ag(s)
Given the concentration you found, what is the value for Q? (If you couldn't solve the first part, use 1.0
x 103 M as the concentration you needed to find so you can solve for Q and continue the problem).
A/
Now solve for E. What is this value? Use 298 K as the temperature and 96485 C/s for F
Transcribed Image Text:Question 4 Since E can be used to determine Q and vice versa, if you know the Ksp of a salt, you can use it to find the cell potential. Imagine a concentration cell in which one half- cell has a silver electrode in a saturated solution of Ag3PO4 and the other half-cell is a silver electrode in a 0.5 M solution of AgNO3. We start with determining the concentration of Ag+ in the saturated solution. The Ksp of silver phosphate is 1.8 x 10-18. What is the solubility of silver phosphate? What is the concentration of Ag+? Now we can use the Nernst equation to find E for our cell: Ag(s) Aga) (saturated conc. A/ A In the Nernst equation, what value will we have for E? A A A/ Now we can use the Nernst equation to find E for our cell: Ag(s) Ag(aq) (saturated conc. .) || Agaq) (0.5 M) | Ag(s) In the Nernst equation, what value will we have for Eº? nc.) || Agaq) (0.5 M) | In the Nernst equation, what value will we have for n? A Ag(s) Given the concentration you found, what is the value for Q? (If you couldn't solve the first part, use 1.0 x 103 M as the concentration you needed to find so you can solve for Q and continue the problem). A/ Now solve for E. What is this value? Use 298 K as the temperature and 96485 C/s for F
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