A galvanic (voltaic) cell consists of an electrode composed of cadmium in a 1.0 M cadmium ion solution and a second electrode composed of cobalt in a 1.0 M cobalt(II) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25oC.
A galvanic (voltaic) cell consists of an electrode composed of cadmium in a 1.0 M cadmium ion solution and a second electrode composed of cobalt in a 1.0 M cobalt(II) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25oC.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A galvanic (voltaic) cell consists of an electrode composed of cadmium in a 1.0 M cadmium ion solution and a second electrode composed of cobalt in a 1.0 M cobalt(II) ion solution, connected by a salt bridge. Calculate the standard potential for this cell at 25oC. Use this list of standard reduction potentials.
![Standard Potential
Reduction Half-Reaction
Ered (V)
F2(g) + 2e → 2F (aq)
+2.87
O3(g) + 2H3O*(aq) + 2e¯ → O2(g) + 3H2O(1)
+2.076
Co (aq) + e → Co2"(aq)
+1.92
H2O2(aq) + 2H3O*(aq) + 2e → 2H20(1)
+1.776
N20(g) + 2H3O*(aq) + 2e¯ → N2(g) + 3H2O(1)
+1.766
3+
Ce+*(aq) + e¯ → Ce*(aq)
+1.72
PbO2(s) + SO4² (aq) + 4H3O*(aq)+ 2e¯ → PbSO4(s) + 6H2O(1)
+1.6913
MnO4 (aq) + 4H3O*(aq) + 3e¯ → MnO2(s) + 6H2O(1)
+1.679
NiO2(s) + 4H3O*(aq) + 2e¯ → Ni²*(aq) + 6H2O(1)
+1.678
|HCIO-(aq) + 2HЗО"(аq) + 2е — HCIO (aq) + зн
O(1)
+1.645
2
2HCIO2(aq) + 6H3O"(aq) + 6e¯ → Cl 2 (g) + 10H
O(1)
+1.628
2HCIO(aq) + 2H3O"(aq) + 2e¯ → Cl2(g) +4H20(1)
+1.611
H5IO6(s) + H3O*(aq) + 2e¯ → I03 (aq) + 4H2O(1)
+1.601
RuO 4° (aq) + 4 H3O' (aq) + 2e → Ruo
2
(ад) + 6H20(1)
+1.6
|2NO(g) + 2H3O*(aq) + 2e¯ → N2O(g) + 3H20(1)
+1.591
IO 4 (aq) + 2H3O"(aq) + 2e¯ → IO 3 (aq) + 3H20(1)
+1.589
MnO4 (aq) + 8H3O*(aq) + 5e¯ → Mn²"(aq) + 12H2O(1)
+1.507
2+
RuO 2 * (aq) + 2 Hҙ0"(aq) + e- —
Ru(OH) 2
(aq) + 2H2O(1)
+1.5
3+
Au"(aq) + 3e
Au(s)
+1.498
|2CIO3 (aq) + 12H3O"(aq) + 10e¯ –→ Cl 2 (g) + 18H 2 O(1)
+1.47
PbO2(s) + 4H3O*(aq)+ 2e¯ → Pb-"(aq) + 6H2O(1)
+1.455
|ClO3 (aq) + 6H3O*(aq) + 6e¯ → CI (aq) + 9H2O(1)
+1.451
BrO3 (aq) + 6H3O*(aq) + 5e - →
1/2B12(1) + 9H2O(1)
+1.482
HOI(aq) + H3O"(aq) + e¯→ 1/2 I 2 (s) + 2H2O(1)
+1.430](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F881daa09-6051-4a13-ad60-a4a63231658f%2F4df6e859-d24c-49f1-af40-763912c97e77%2Fahys5ab_processed.png&w=3840&q=75)
Transcribed Image Text:Standard Potential
Reduction Half-Reaction
Ered (V)
F2(g) + 2e → 2F (aq)
+2.87
O3(g) + 2H3O*(aq) + 2e¯ → O2(g) + 3H2O(1)
+2.076
Co (aq) + e → Co2"(aq)
+1.92
H2O2(aq) + 2H3O*(aq) + 2e → 2H20(1)
+1.776
N20(g) + 2H3O*(aq) + 2e¯ → N2(g) + 3H2O(1)
+1.766
3+
Ce+*(aq) + e¯ → Ce*(aq)
+1.72
PbO2(s) + SO4² (aq) + 4H3O*(aq)+ 2e¯ → PbSO4(s) + 6H2O(1)
+1.6913
MnO4 (aq) + 4H3O*(aq) + 3e¯ → MnO2(s) + 6H2O(1)
+1.679
NiO2(s) + 4H3O*(aq) + 2e¯ → Ni²*(aq) + 6H2O(1)
+1.678
|HCIO-(aq) + 2HЗО"(аq) + 2е — HCIO (aq) + зн
O(1)
+1.645
2
2HCIO2(aq) + 6H3O"(aq) + 6e¯ → Cl 2 (g) + 10H
O(1)
+1.628
2HCIO(aq) + 2H3O"(aq) + 2e¯ → Cl2(g) +4H20(1)
+1.611
H5IO6(s) + H3O*(aq) + 2e¯ → I03 (aq) + 4H2O(1)
+1.601
RuO 4° (aq) + 4 H3O' (aq) + 2e → Ruo
2
(ад) + 6H20(1)
+1.6
|2NO(g) + 2H3O*(aq) + 2e¯ → N2O(g) + 3H20(1)
+1.591
IO 4 (aq) + 2H3O"(aq) + 2e¯ → IO 3 (aq) + 3H20(1)
+1.589
MnO4 (aq) + 8H3O*(aq) + 5e¯ → Mn²"(aq) + 12H2O(1)
+1.507
2+
RuO 2 * (aq) + 2 Hҙ0"(aq) + e- —
Ru(OH) 2
(aq) + 2H2O(1)
+1.5
3+
Au"(aq) + 3e
Au(s)
+1.498
|2CIO3 (aq) + 12H3O"(aq) + 10e¯ –→ Cl 2 (g) + 18H 2 O(1)
+1.47
PbO2(s) + 4H3O*(aq)+ 2e¯ → Pb-"(aq) + 6H2O(1)
+1.455
|ClO3 (aq) + 6H3O*(aq) + 6e¯ → CI (aq) + 9H2O(1)
+1.451
BrO3 (aq) + 6H3O*(aq) + 5e - →
1/2B12(1) + 9H2O(1)
+1.482
HOI(aq) + H3O"(aq) + e¯→ 1/2 I 2 (s) + 2H2O(1)
+1.430
![[Co(NH3)6]"(aq) + e¯ → [Co(NH3)6]**(aq)
|-0.108
Pb2"(aq) + 2e
→ Pb(s)
|-0.13
Sn2"(aq) + 2e
Sn(s)
|-0.14
O2(g) + 2H20(1) + 2e¯ → H2O2(1) + 20H (aq)
|-0.146
AgI(s) + e → Ag(s) + I¯ (aq)
|-0.15224
|CO2(g) + 2H3O+(aq) + 2e¯ → HCO2H(s) + 2H2O(1)
|-0.199
Cu(OH)2(s) + 2e¯ → Cu(s) + 20H (aq)
-0.222
Ni2" (aq) + 2e → Ni(s)
-0.26
Со- (аq) + 2е
Co(s)
|-0.28
PbSO4(s) + 2e → Pb(s) + SO4² (aq)
|-0.3588
SeO32 (aq) + 3H2O(1) + 4e
Se + 60H¯(aq)
-0.366
Cd2*(aq) + 2e -→ Cd(s)
-0.403
Cr*(aq) + e
• Cr²+(
*(aq)
-0.407
|Cu(CN)2- (aq) + e
Cu(s) + 2CN - (aq)
-0.429
Fe2*(aq) + 2e→ Fe(s)
|-0.44
NO2 (g) + H2O(1)+ 3e
NO(g) + 20H (aq)
|-0.46
S(s) + 2e → S² (aq)
-0.48
2CO2(g) + 2H3O*(aq) + 2e¯ → H2C2O4(s) + H2O(1)
-0.49
|TiO2(s) + 4H3O*+ 2e¯ → Ti²"(aq) + 6H2O(1)
|-0.502
Au(CN)2 - (aq) +e¯ → Au(s) + 20CN (aq)
|-0.60
Cr*(aq) + 3e
Cr(s)
-0.74
Zn-"(aq) + 2e¯→ Zn(s)
|-0.76
Cd(OH)2(s) + 2e ¯→ Cd(s) + 20H-(aq)
-0.809
| 2H2O(1) + 2e¯ → H2(g) + 20H¯(aq)
-0.83](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F881daa09-6051-4a13-ad60-a4a63231658f%2F4df6e859-d24c-49f1-af40-763912c97e77%2Fdjujjmn_processed.png&w=3840&q=75)
Transcribed Image Text:[Co(NH3)6]"(aq) + e¯ → [Co(NH3)6]**(aq)
|-0.108
Pb2"(aq) + 2e
→ Pb(s)
|-0.13
Sn2"(aq) + 2e
Sn(s)
|-0.14
O2(g) + 2H20(1) + 2e¯ → H2O2(1) + 20H (aq)
|-0.146
AgI(s) + e → Ag(s) + I¯ (aq)
|-0.15224
|CO2(g) + 2H3O+(aq) + 2e¯ → HCO2H(s) + 2H2O(1)
|-0.199
Cu(OH)2(s) + 2e¯ → Cu(s) + 20H (aq)
-0.222
Ni2" (aq) + 2e → Ni(s)
-0.26
Со- (аq) + 2е
Co(s)
|-0.28
PbSO4(s) + 2e → Pb(s) + SO4² (aq)
|-0.3588
SeO32 (aq) + 3H2O(1) + 4e
Se + 60H¯(aq)
-0.366
Cd2*(aq) + 2e -→ Cd(s)
-0.403
Cr*(aq) + e
• Cr²+(
*(aq)
-0.407
|Cu(CN)2- (aq) + e
Cu(s) + 2CN - (aq)
-0.429
Fe2*(aq) + 2e→ Fe(s)
|-0.44
NO2 (g) + H2O(1)+ 3e
NO(g) + 20H (aq)
|-0.46
S(s) + 2e → S² (aq)
-0.48
2CO2(g) + 2H3O*(aq) + 2e¯ → H2C2O4(s) + H2O(1)
-0.49
|TiO2(s) + 4H3O*+ 2e¯ → Ti²"(aq) + 6H2O(1)
|-0.502
Au(CN)2 - (aq) +e¯ → Au(s) + 20CN (aq)
|-0.60
Cr*(aq) + 3e
Cr(s)
-0.74
Zn-"(aq) + 2e¯→ Zn(s)
|-0.76
Cd(OH)2(s) + 2e ¯→ Cd(s) + 20H-(aq)
-0.809
| 2H2O(1) + 2e¯ → H2(g) + 20H¯(aq)
-0.83
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