sin- & cos(ma) + sin (md)] (cos 6-1) If F[ - 5 in 4 cos ( (m-1) 4) + Sin (cm-1) 1) ] = (Rcos 6-1) [ -=-51 0) - (Ro36-1) (cos 4 - 1) then Show that = KTT [Kis am any integer] m

Q: Suppose that sin(0)=3/7. What sec(0)=____ Your Answer: (round to 3 decimal places)

A: Given sinθ = 37

Q: Show that cos 2x-cos 6x sin 6x-sin 2x b) Hence or otherwise, solve = tan 4x cos 4x cos 2x-cos 4x cos…

A: Hence proved

Q: 1) cos²¹ (-²) == 2) arctan (-1) = (Cos-c2tant can -12-09-0 27 4) arcsec (2) (-4) arctanc-10-27 5)…

A:

Q: 6) Prove cos4x -sin+x= cos 2x

A:

Q: ) cos(cos-¹(35)) ) sec(tan-¹(5)) csc(sin-¹(n)) ) cos ¹(cos(29°)) (4π) 5 =) sin ¹[sin ]]

A:

Q: Ísin^8 (3z) cos^5 (3z) dz * O 1/27 cos^9 (3z) - 2/33 cos^11 (3z) + 1/39 cos^13 (3z) + C O 1/27 sin^9…

A: Given integral I=∫ sin8(3z) cos5(3z)  dz

Q: prove cos(n*pi) = (-1)^n

A: To prove: cosnπ=-1n

Q: tan 0 cos²0 = 2 tan 0 cos² 0 - tan 0 1tan²0

A:

Q: 2 sin 0 + sin 2 0 =0 with 0degrees

A: To solve:2sin0+sin20=0