tan 0 cos²0 = 2 tan 0 cos² 0 - tan 0 1tan²0

Q: what is cos(tan^−1(−1/2))

A:

Q: Find the exact value of the expression whenever it is defined.

A: (a) sin-1-22 -π2≤x≤π2 sin x=-22 multiply and divide by 12 sin x =12  sin x = π4 sin-1-22=π4

Q: n¹(tan(-)) 215. tan

A: Given problem:- tan-1tan-π6

Q: If tanx = (a/b) find the value of (cosx+sinx)/(cosx-sinx)

A:

Q: 2nd eg- how to derive tan^2x

A:

Q: cos(tan^-1 12/5 - tan^-1 4/3) simplify the exact value. rationalize fraction

A:

Q: What is the real number equivalent for sin ( Cos ^ -1 ( 1/2)) ?

A:

Q: csc tan ²¹ (-1)] = sec cos ¹ (-1/2) = -1

A: odd function even function

Q: 8.) k(x)=-2 tan(2(x+)) Period = Increment =

A: Given function is: kx=-2tan2x+π8 Then the period of this function is 2π2=π. The increment is π8.

Q: Evalnate without using Calculator (^) Cos 2 () -9 (6) Sin 15°

A: a) We know that Therefore, we have

Q: 5. tant x + tan2 x = tan? x sec2 x

A:

Q: sin @ 225

A: We have to find value of sin(225∘)

Q: which one of the following is the same as sin(tan^-12/x) a. x/sqrt x^2+4 b. 2/sqrtx^2+4 c. sqrt…

A:

Q: If cos x = 4/5, csc x < 0, then sin 2x cos2x = tan 2x

A: Cosx=4/5 ,cscx&lt;0

Q: Find cos(sin^−1(−1/2))

A: Trigonometric

Q: (cos7x-cos5x)/(cos7+cos5x)=tan6xtanx

A: