tan 0 cos²0 = 2 tan 0 cos² 0 - tan 0 1tan²0

Q: Evaluate the following leaving the result as an EXACT value. cos⁡(tan^-1⁡(4/3)+sin^−1⁡(−2/5))

A: We have to solve the problem

Q: Cos^-1 (cos(-60*)) Answer in degrees pls.

A: Solution is given below:

Q: Solve 8-3 cos x = cos x-3 to two decimal places; - << T.

A: Given 8 - 3cosx = cosx - 3

Q: what is cos(tan^−1(−1/2))

A:

Q: simplify  tan(cos^-1(x))

A:

Q: Find the exact value of the expression whenever it is defined.

A: (a) sin-1-22 -π2≤x≤π2 sin x=-22 multiply and divide by 12 sin x =12  sin x = π4 sin-1-22=π4

Q: What is the real number equivalent for sin ( Cos ^ -1 ( 1/2)) ?

A:

Q: csc tan ²¹ (-1)] = sec cos ¹ (-1/2) = -1

A: odd function even function

Q: 8.) k(x)=-2 tan(2(x+)) Period = Increment =

A: Given function is: kx=-2tan2x+π8 Then the period of this function is 2π2=π. The increment is π8.

Q: Evalnate without using Calculator (^) Cos 2 () -9 (6) Sin 15°

A: a) We know that Therefore, we have

Q: Solve 4 tan x * cos^2 x = 1 for 0 ^ 0

A:

Q: 5. tant x + tan2 x = tan? x sec2 x

A:

Q: do you solve cos(tan-1(2/3))

A:

Q: which one of the following is the same as sin(tan^-12/x) a. x/sqrt x^2+4 b. 2/sqrtx^2+4 c. sqrt…

A:

Q: If cos x = 4/5, csc x < 0, then sin 2x cos2x = tan 2x

A: Cosx=4/5 ,cscx&lt;0

Q: Find cos(sin^−1(−1/2))

A: Trigonometric