Simple random sampling uses a sample of size n from a population of size N to obtain data that can be used to make inferences about the characteristics of a population. Suppose that, from a population of 55 bank accounts, we want to take a random sample of six accounts in order to learn about the population. How many different random samples of six accounts are possible?

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**Simple Random Sampling in Statistics**

In statistics, **simple random sampling** involves selecting a subset of individuals from a larger population. The sample size (n) is drawn from a population of size (N). The objective is to obtain data that can be used to make inferences about the characteristics of the entire population.

**Example Scenario:**

Consider a population of 55 bank accounts. Our goal is to take a random sample of six (6) accounts to study the population characteristics.

**Question:**

How many different random samples of six accounts can be possible from this population?

---

**Solution:**

To determine the number of different possible samples, we use the **combination formula**:

\[ \binom{N}{n} = \frac{N!}{n!(N-n)!} \]

In this scenario:
- \( N = 55 \)
- \( n = 6 \)

Plugging in the values, we calculate:

\[ \binom{55}{6} = \frac{55!}{6!(55-6)!} = \frac{55!}{6! \cdot 49!} \]

By calculating this value, we obtain the number of different possible random samples of six accounts that can be selected from a population of 55 bank accounts.
Transcribed Image Text:**Simple Random Sampling in Statistics** In statistics, **simple random sampling** involves selecting a subset of individuals from a larger population. The sample size (n) is drawn from a population of size (N). The objective is to obtain data that can be used to make inferences about the characteristics of the entire population. **Example Scenario:** Consider a population of 55 bank accounts. Our goal is to take a random sample of six (6) accounts to study the population characteristics. **Question:** How many different random samples of six accounts can be possible from this population? --- **Solution:** To determine the number of different possible samples, we use the **combination formula**: \[ \binom{N}{n} = \frac{N!}{n!(N-n)!} \] In this scenario: - \( N = 55 \) - \( n = 6 \) Plugging in the values, we calculate: \[ \binom{55}{6} = \frac{55!}{6!(55-6)!} = \frac{55!}{6! \cdot 49!} \] By calculating this value, we obtain the number of different possible random samples of six accounts that can be selected from a population of 55 bank accounts.
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