Part i) The proportion of the 126 people who are living below the poverty line, 25/126, is a: A. variable of interest. B. parameter. C. statistic. Part ii) Use the sample data to compute a 95% confidence interval for the true proportion of Gastown residents living below the poverty line. (Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest four decimal places). 95% confidence interval= ( ⠀
Part i) The proportion of the 126 people who are living below the poverty line, 25/126, is a: A. variable of interest. B. parameter. C. statistic. Part ii) Use the sample data to compute a 95% confidence interval for the true proportion of Gastown residents living below the poverty line. (Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest four decimal places). 95% confidence interval= ( ⠀
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these social outreach programs should be located based on the percentage of residents living below the poverty line in each region of the city. He takes a simple random sample of 126 people living in Gastown and finds that 25 have an annual income that is below the poverty line.

Transcribed Image Text:Part
i) The proportion of the 126 people who are living below the poverty line, 25/126, is a:
A. variable of interest.
B. parameter.
C. statistic.
Part ii) Use the sample data to compute a 95% confidence interval for the true proportion of Gastown residents living
below the poverty line.
(Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest four
decimal places).
95% confidence interval = (
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