Silver metal is recovered during the reduction of silver nitrate: Cu(s) + 2 AgNO3(aq) → 2 Ag(s) + Cu(NO3)2(aq) During an experiment, 125 g of tion containing 275 g AgNO,.u were placed into a solu- 135 g Ag were recovered. What is the percent yield of Ag obtained?
Silver metal is recovered during the reduction of silver nitrate: Cu(s) + 2 AgNO3(aq) → 2 Ag(s) + Cu(NO3)2(aq) During an experiment, 125 g of tion containing 275 g AgNO,.u were placed into a solu- 135 g Ag were recovered. What is the percent yield of Ag obtained?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![### Title: Silver Recovery via Reduction Reaction
In this example, silver metal is recovered during the reduction of silver nitrate:
\[ \text{Cu}(s) + 2 \text{AgNO}_3(aq) \rightarrow 2 \text{Ag}(s) + \text{Cu(NO}_3)_2(aq) \]
**Problem Statement:**
During an experiment, 125 grams of copper (Cu) were placed into a solution containing 275 grams of silver nitrate (AgNO₃). As a result, 135 grams of silver (Ag) were recovered. The task is to determine the percent yield of the silver (Ag) obtained.
**Details:**
- **Cu (Copper):** 125 grams
- **AgNO₃ (silver nitrate):** 275 grams
- **Recovered Ag (Silver):** 135 grams
**Objective:**
Calculate the percent yield of silver (Ag) obtained from the reaction.
**Percent Yield Calculation:**
Percent yield is calculated as follows:
\[ \text{Percent Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100 \]
For this reaction:
- Find the theoretical yield of silver (Ag) using stoichiometry.
- Use the given actual yield (135 grams) to compute the percent yield.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F538c38f2-df06-499f-a780-26c93cfeecb7%2F23318637-34d9-4f37-8b94-3da304028d45%2Fgdxad3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Title: Silver Recovery via Reduction Reaction
In this example, silver metal is recovered during the reduction of silver nitrate:
\[ \text{Cu}(s) + 2 \text{AgNO}_3(aq) \rightarrow 2 \text{Ag}(s) + \text{Cu(NO}_3)_2(aq) \]
**Problem Statement:**
During an experiment, 125 grams of copper (Cu) were placed into a solution containing 275 grams of silver nitrate (AgNO₃). As a result, 135 grams of silver (Ag) were recovered. The task is to determine the percent yield of the silver (Ag) obtained.
**Details:**
- **Cu (Copper):** 125 grams
- **AgNO₃ (silver nitrate):** 275 grams
- **Recovered Ag (Silver):** 135 grams
**Objective:**
Calculate the percent yield of silver (Ag) obtained from the reaction.
**Percent Yield Calculation:**
Percent yield is calculated as follows:
\[ \text{Percent Yield} = \left( \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \right) \times 100 \]
For this reaction:
- Find the theoretical yield of silver (Ag) using stoichiometry.
- Use the given actual yield (135 grams) to compute the percent yield.
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