- Show that the equation of the circle passing through (1, 1) and the points of intersection of the circle x² + y² + 13x − 3y = 0 and 2x² + 2y² + 4x −7y - 25 = 0 is 4x² + 4y² + 30x − 13y - 25 = 0. -
- Show that the equation of the circle passing through (1, 1) and the points of intersection of the circle x² + y² + 13x − 3y = 0 and 2x² + 2y² + 4x −7y - 25 = 0 is 4x² + 4y² + 30x − 13y - 25 = 0. -
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter7: Conic Sections And Quadratic Systems
Section7.1: The Circle And The Parabola
Problem 88E
Related questions
Question
![Show that the equation of the circle passing through (1, 1) and
the points of intersection of the circle x² + y² + 13x − 3y = 0
and 2x² + 2y² + 4x − 7y - 25 = 0 is 4x² + 4y² + 30x − 13y – 25 = 0.
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F79a64c29-0533-474b-8c65-81db721283d9%2F0e6f842e-dd80-496c-90aa-a37c691278cb%2Fuswswj_processed.png&w=3840&q=75)
Transcribed Image Text:Show that the equation of the circle passing through (1, 1) and
the points of intersection of the circle x² + y² + 13x − 3y = 0
and 2x² + 2y² + 4x − 7y - 25 = 0 is 4x² + 4y² + 30x − 13y – 25 = 0.
-
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