Find the x² + y² − 3x − 6y + 14 = 0, - equation of the circle which cuts th x² + y² − x − 4y + 8 = 0 and x² + y² + 2x − 6y + 9 = 0 orthogonally.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section: Chapter Questions
Problem 8RE
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Find the equation of the circle which cuts the three circles
x² + y² − 3x − 6y + 14 = 0,
x² + y² - x - 4y + 8 = 0
and
x² + y² + 2x − 6y + 9 = 0 orthogonally.
Transcribed Image Text:Find the equation of the circle which cuts the three circles x² + y² − 3x − 6y + 14 = 0, x² + y² - x - 4y + 8 = 0 and x² + y² + 2x − 6y + 9 = 0 orthogonally.
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