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A circle can be defined by an equation x² + y² + ax +by+c= 1. Find an equation of a circle that passes through (-5, 0), (0, 0) and (0, -7). Ox² + y² +7x + 5y − 1 = 0 Ox² + y² + 2x + 3y + 2 = 0 Ox² + y² + 5x + 7y + 1 = 1 Ox² + y² + 3x + 2y + 1 = 1

A circle can be defined by an equation x² + y² + ax +by+c= 1. Find an equation of a circle that passes through (-5, 0), (0, 0) and (0, -7). Ox² + y² +7x + 5y − 1 = 0 Ox² + y² + 2x + 3y + 2 = 0 Ox² + y² + 5x + 7y + 1 = 1 Ox² + y² + 3x + 2y + 1 = 1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A circle can be defined by an equation x² + y² + ax +by+ c = 1. Find an equation of a circle that passes through (-5, 0), (0, 0) and (0, -7). Ox² + y² + 7x + 5y-1=0 x² + y² + 2x + 3y + 2 = 0 2 Ox² + y² + 5x + 7y + 1 = 1 I O x² + y² + 3x + 2y + 1 = 1
Transcribed Image Text:A circle can be defined by an equation x² + y² + ax +by+ c = 1. Find an equation of a circle that passes through (-5, 0), (0, 0) and (0, -7). Ox² + y² + 7x + 5y-1=0 x² + y² + 2x + 3y + 2 = 0 2 Ox² + y² + 5x + 7y + 1 = 1 I O x² + y² + 3x + 2y + 1 = 1
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