Show that the conditional probability P (A | B) of events A and B satisfies the three axioms of a probability, that is, (a) P(A/B) ≥0 (b) P(S |B) = 1 P((A₂A₂) | B) = P(A₁ | B) + P(A₂ | B), _if A₁ A₂ = þ.

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Show that the conditional probability P (AB) of events A and B satisfies the three axioms of
a probability, that is,
(a)
P(A/B) ≥0
(b)
P(S |B) = 1
P((A₁A₂) | B) = P(A₁ | B) + P(A₂ | B), if A₁ A₂ = 0.
Transcribed Image Text:Show that the conditional probability P (AB) of events A and B satisfies the three axioms of a probability, that is, (a) P(A/B) ≥0 (b) P(S |B) = 1 P((A₁A₂) | B) = P(A₁ | B) + P(A₂ | B), if A₁ A₂ = 0.
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