Let X and Y be two possible events with P(X) = 0.38 and P(Y) = 0.23 respectively.Assume that events X and Y are mutually exclusive.Calculate the probability of the event X or Y i.e., P(X or Y)? (Round to 4 decimals)

Answer: From the given data, P(X) = 0.38 P(Y) = 0.23

Answered: Let X and Y be two possible events with…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Let X and Y be two possible events with P(X) = 0.38 and P(Y) = 0.23 respectively. Assume that events X and Y are mutually exclusive. Calculate the probability of the event X or Y i.e., P(X or Y)? (Round to 4 decimals)