Show in Figure 1 is the water flow system. The velocity head difference is .  Volume flow rate is .  The heights are  and , respectively.  The power output from the motor is , . The energy added by the pump is . The energy loss between point 1 and 2 is . Calculate  2)  he energy removed from the system   in meter. ___________m

Elements Of Electromagnetics
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Show in Figure 1 is the water flow system. The velocity head difference is .  Volume flow rate is .  The heights are  and , respectively.  The power output from the motor is , . The energy added by the pump is . The energy loss between point 1 and 2 is .

Calculate  2)  he energy removed from the system   in meter. ___________m

Show in Figure 1 is the water flow system. The velocity head difference is
v²₁-v²₂
-= 2.0m. Volume flow rate is 0.5 m³/s. The heights are h1 = 1.0 m and
2g
h2=2.0 m, respectively. The power output from the motor is P = 7.848 kW,
e M, motor = 80%. The energy added by the pump is h = 3.0 m. The energy loss
between point 1 and 2 is h₁ = 0.2 m.
Calculate 2) he energy removed from the system h in meter.
Motor
Pump
Valve
Flow
h2
Motor
m
Transcribed Image Text:Show in Figure 1 is the water flow system. The velocity head difference is v²₁-v²₂ -= 2.0m. Volume flow rate is 0.5 m³/s. The heights are h1 = 1.0 m and 2g h2=2.0 m, respectively. The power output from the motor is P = 7.848 kW, e M, motor = 80%. The energy added by the pump is h = 3.0 m. The energy loss between point 1 and 2 is h₁ = 0.2 m. Calculate 2) he energy removed from the system h in meter. Motor Pump Valve Flow h2 Motor m
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