show-all-working-explaining-detailly-each-step.Answer should be typewritten using a computer keyboard. Using the following half-cell equations andtheir standard electrode potentials:Fe" (aq) + e5 Fe2 (aq) E =+0.77 VCu"aq) + 2e 5 Cu(s) E = +0.34 Vwhat is the cell diagram?A Pt Fe"aq), Fe"(aq) || Cu'" (aq) | Cu(s)B Cu (aq)| Cu(s) || Fe2"aq), Fe'"(aq) |32.%3DPtC Cu(s) |Cu²"(aq)|| Fe²"(aq), Fe"(aq) |PtD Pt| Fe" (aq), Fe2"aq) || Cu(s) |Cu"(aq)

Fe+3 will get reduced because Fe+3 has high reduction potential while Cu will oxidised because…

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Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter18: Introduction To Electrochemistry

Section: Chapter Questions

Problem 18.4QAP

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show-all-working-explaining-detailly-each-step.

Answer should be typewritten using a computer keyboard.

Using the following half-cell equations and
their standard electrode potentials:
Fe" (aq) + e5 Fe2 (aq) E =+0.77 V
Cu"aq) + 2e 5 Cu(s) E = +0.34 V
what is the cell diagram?
A Pt Fe"aq), Fe"(aq) || Cu'" (aq) | Cu(s)
B Cu (aq)| Cu(s) || Fe2"aq), Fe'"(aq) |
32.
%3D
Pt
C Cu(s) |Cu²"(aq)|| Fe²"(aq), Fe"(aq) |
Pt
D Pt| Fe" (aq), Fe2"aq) || Cu(s) |
Cu"(aq)

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