Shear stress (KN/m2) q = 50 kN/m: 5= 50 kN/m² (+50, +50) D C M n= 50 kN/m² 29.3 170.7 0; = 150 kN/m² Normal stress 10 (kN/m² ) Q(+164, – 29.9) N(+150, – 50)

Q: SITUATION 1 The system below is consisting of two solid circular cross-section bars AB and BC,…

A: The length of member ABC  = 1700mm.Diameter of bar BC, ∅BC = 50mmLength of bar BC, LBC =…

Q: Draw the stress and bending moment diagrams for the frame shown. EI is constant. Use the force…

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Q: PROBLEM 1: The homogeneous structure shown weighs 21.45 kN per square meter of cross-section. The…

A: The homogeneous structure shown weighs (w) = 21.45 kN/m2 of cross-section.

Q: average

A:

Q: Situation X:A hollow cylindrical vessel 1.8 m high has an outside diameter of 450 mm and an inside…

A:

Q: Consider the given figure. Given: P = 12 kN. P A C-0000 ←0.4 m→ 2 kN/m 13.6 KN -0.8 m- Determine the…

A:

Q: 12 kN • m •m C D B W250 X 80 -1.2 m--1.6 m- t-1.2 m-

A:

Q: A. Calculate for the shear Force in kN at member ED of the frame shown in figure 1 using Portal…

A: Given data:

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.