SHEAR and MOMENT DIAGRAMS in BEAMS Sample Problem No. 3: Draw the shear and bending - moment diagrams for beam AB. Also determine the maximum bending-moment. All pulleys have a 600 mm diameter. Ax Step 1: Draw the free body diagram EMA=0 ΣF, = 0 Ay Ax = 50 50 kN 3m 45.78 50 kN Ay = 45.78 3m Step 3: Forces Diagram Step 2: Compute the reactions at the support Σ F= 0 ; - Ax + 50 = 0; Ax= 50 kN <<< 3m 1m 7m -4.22 7m 50 187.34 Step 4: Shear and moment diagrams 137.34 50 50(3.300)-50(1+.300) - By(16.6)=0; Ay+By-50=0; Ay= 45.78 kN KN↑ 7m -54.22 0.6m d 50 0.6m 1m ).... 0.6m 1m 1m 157.8 1m 75.3 25.3 1m 6m 50 kN Step 5: Determine the maximum bending moment: Therefore: Max. Moment = 187.34 kN-m occur at point b. 6m 6m There are moments at c, d and e. M = 50 kN (1m) = 50 kN -m Mc = 50 kN-m clockwise ; Md and Me= 50 kN-m counter clockwise 50 By By = 4.22 kN By = 4.22 kN B B -4.22 By = 4.22

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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Note: Solve the exercise #2 problem with the same way and steps on how the sample problem #3 was solved.

SHEAR and MOMENT DIAGRAMS in BEAMS
Sample Problem No. 3: Draw the shear and bending moment diagrams for beam AB.
Also determine the maximum bending-moment. All pulleys have a 600 mm diameter.
Ax
Step 1: Draw the free body diagram
A
Ax = 50
Ay
50 kN
3m
45.78
Ay = 45.78
50 kN
Step 3: Forces Diagram
3m
3m
1ml
-4.22
C
7m
187.34
50
137.34
7m
Step 4: Shear and moment diagrams
50
Step 2: Compute the reactions at the support
ΣΕ= 0 ; - Ax + 50 = 0; Ax= 50 kN
ΣM₁ = 0; 50(3-.300)-50(1+. 300) - By(16.6) = 0 ; By = 4.22 kN
78 KN↑
ΣF, = 0; Ay+By-50=0; Ay= 45.78 KN
7m
-54.22
0.6m
50
0.6m
0.6m
1m
!1m
157.8
1m
Ý...
75.3
25.3
1m
1m
6m
50 kN
Step 5: Determine the maximum bending moment:
Therefore: Max. Moment=187.34 kN-m occur at point b.
6m
There are moments at c, d and e. M = 50 kN (1m) = 50 kN -m
Mc = 50 kN-m clockwise ; Md and Me = 50 kN-m counter clockwise
6m
50
By
B
B
-4.22
By = 4.22
Transcribed Image Text:SHEAR and MOMENT DIAGRAMS in BEAMS Sample Problem No. 3: Draw the shear and bending moment diagrams for beam AB. Also determine the maximum bending-moment. All pulleys have a 600 mm diameter. Ax Step 1: Draw the free body diagram A Ax = 50 Ay 50 kN 3m 45.78 Ay = 45.78 50 kN Step 3: Forces Diagram 3m 3m 1ml -4.22 C 7m 187.34 50 137.34 7m Step 4: Shear and moment diagrams 50 Step 2: Compute the reactions at the support ΣΕ= 0 ; - Ax + 50 = 0; Ax= 50 kN ΣM₁ = 0; 50(3-.300)-50(1+. 300) - By(16.6) = 0 ; By = 4.22 kN 78 KN↑ ΣF, = 0; Ay+By-50=0; Ay= 45.78 KN 7m -54.22 0.6m 50 0.6m 0.6m 1m !1m 157.8 1m Ý... 75.3 25.3 1m 1m 6m 50 kN Step 5: Determine the maximum bending moment: Therefore: Max. Moment=187.34 kN-m occur at point b. 6m There are moments at c, d and e. M = 50 kN (1m) = 50 kN -m Mc = 50 kN-m clockwise ; Md and Me = 50 kN-m counter clockwise 6m 50 By B B -4.22 By = 4.22
Exercise No. 2: Draw the shear and bending moment diagrams for beam AD. Also
determine the maximum bending-moment. All pulleys have a 600 mm diameter.
50 KN
2m
b
A
1.2m
T
1.2m!
V
3m
1m
/30 KN
4
3m
D
Note: Make your drawings clearly and if possible all dimensions must be on scale.
Score for laboratory requirement is based on Rubric grading system.
Transcribed Image Text:Exercise No. 2: Draw the shear and bending moment diagrams for beam AD. Also determine the maximum bending-moment. All pulleys have a 600 mm diameter. 50 KN 2m b A 1.2m T 1.2m! V 3m 1m /30 KN 4 3m D Note: Make your drawings clearly and if possible all dimensions must be on scale. Score for laboratory requirement is based on Rubric grading system.
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