SHEAR and MOMENT DIAGRAMS in BEAMS Sample Problem No. 3: Draw the shear and bending - moment diagrams for beam AB. Also determine the maximum bending-moment. All pulleys have a 600 mm diameter. Ax Step 1: Draw the free body diagram EMA=0 ΣF, = 0 Ay Ax = 50 50 kN 3m 45.78 50 kN Ay = 45.78 3m Step 3: Forces Diagram Step 2: Compute the reactions at the support Σ F= 0 ; - Ax + 50 = 0; Ax= 50 kN <<< 3m 1m 7m -4.22 7m 50 187.34 Step 4: Shear and moment diagrams 137.34 50 50(3.300)-50(1+.300) - By(16.6)=0; Ay+By-50=0; Ay= 45.78 kN KN↑ 7m -54.22 0.6m d 50 0.6m 1m ).... 0.6m 1m 1m 157.8 1m 75.3 25.3 1m 6m 50 kN Step 5: Determine the maximum bending moment: Therefore: Max. Moment = 187.34 kN-m occur at point b. 6m 6m There are moments at c, d and e. M = 50 kN (1m) = 50 kN -m Mc = 50 kN-m clockwise ; Md and Me= 50 kN-m counter clockwise 50 By By = 4.22 kN By = 4.22 kN B B -4.22 By = 4.22
SHEAR and MOMENT DIAGRAMS in BEAMS Sample Problem No. 3: Draw the shear and bending - moment diagrams for beam AB. Also determine the maximum bending-moment. All pulleys have a 600 mm diameter. Ax Step 1: Draw the free body diagram EMA=0 ΣF, = 0 Ay Ax = 50 50 kN 3m 45.78 50 kN Ay = 45.78 3m Step 3: Forces Diagram Step 2: Compute the reactions at the support Σ F= 0 ; - Ax + 50 = 0; Ax= 50 kN <<< 3m 1m 7m -4.22 7m 50 187.34 Step 4: Shear and moment diagrams 137.34 50 50(3.300)-50(1+.300) - By(16.6)=0; Ay+By-50=0; Ay= 45.78 kN KN↑ 7m -54.22 0.6m d 50 0.6m 1m ).... 0.6m 1m 1m 157.8 1m 75.3 25.3 1m 6m 50 kN Step 5: Determine the maximum bending moment: Therefore: Max. Moment = 187.34 kN-m occur at point b. 6m 6m There are moments at c, d and e. M = 50 kN (1m) = 50 kN -m Mc = 50 kN-m clockwise ; Md and Me= 50 kN-m counter clockwise 50 By By = 4.22 kN By = 4.22 kN B B -4.22 By = 4.22
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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