Part A Review Learning Goal: To apply the method of sections to find the forces in specific members of a truss. The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is in equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members of a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawn and the equations of equilibrium are applied: ΣΕ = 0 Σ Ε = 0 Στο = 0 Because there are only three independent equilibrium equations, section cuts should be made such that there are not more than three members that have unknown forces. As shown, a truss is loaded by the forces P₁ = 501 lb and P2 = 210 lb and has the dimension a = 9.50 ft. P₁ B T a/2 C * a/2 H -P₂ E Determine FBC, the magnitude of the force in member BC, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. Express your answer numerically in pounds to three significant figures. ▸ View Available Hint(s) 1 ΑΣΦ Η vec FBC = Submit Part B Complete previous part(s) ? lbs
Part A Review Learning Goal: To apply the method of sections to find the forces in specific members of a truss. The method of sections is used to find the force in a specific member of a truss and is based on the principle that, if a body is in equilibrium, then every part of that body is also in equilibrium. When applied, the method of sections "cuts" or sections the members of a truss and exposes their internal forces. To find the unknown internal member forces, the free-body diagram of a section is drawn and the equations of equilibrium are applied: ΣΕ = 0 Σ Ε = 0 Στο = 0 Because there are only three independent equilibrium equations, section cuts should be made such that there are not more than three members that have unknown forces. As shown, a truss is loaded by the forces P₁ = 501 lb and P2 = 210 lb and has the dimension a = 9.50 ft. P₁ B T a/2 C * a/2 H -P₂ E Determine FBC, the magnitude of the force in member BC, using the method of sections. Assume for your calculations that each member is in tension, and include in your response the sign of each force that you obtain by applying this assumption. Express your answer numerically in pounds to three significant figures. ▸ View Available Hint(s) 1 ΑΣΦ Η vec FBC = Submit Part B Complete previous part(s) ? lbs
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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