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Shaft ABC comprises a brass section AB and a steel section BC with different diameters shown in the diagram below. A lever is located at B with a force F applied at its end. What is the required diameter of the steel section in order to support 70% of the total applied torque to the shaft given the following parameters: d₁ = 90mm Gs = 75MPa Gb === 40MPa Give your answer in mm. T 2m B 0.45m A C dp ds A 2M B 0.45 Steel brass 701 Torque supponed by steel TS = 0.7TT Total :. Tb = 0·35+ Torque OAC = 0 BC + OAB OAC = 0 · OBC = OAB Ts Ls GsJs " 077-(0.45) Tb Lb GbJb 75×10 6 x πTds² 0.4315 32 2 75X106X Tids² 32 0315 x 32 GS 75MPa Gb = 40MP : db = • 90mm ds = ? 0.37 + ( 2 ) T 40x106x 7d2b = 0-6 11 75x106x πds 2 10.08 32 40×106x πdb² 32 11 75 X 10.6 x πids 2 0-6x32 40 x 106 x 71 x0.092 19.2 400106 XA CO09) 10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052 ds = 47.62mm X 65.47mm

Shaft ABC comprises a brass section AB and a steel section BC with different diameters shown in the diagram below. A lever is located at B with a force F applied at its end. What is the required diameter of the steel section in order to support 70% of the total applied torque to the shaft given the following parameters: d₁ = 90mm Gs = 75MPa Gb === 40MPa Give your answer in mm. T 2m B 0.45m A C dp ds A 2M B 0.45 Steel brass 701 Torque supponed by steel TS = 0.7TT Total :. Tb = 0·35+ Torque OAC = 0 BC + OAB OAC = 0 · OBC = OAB Ts Ls GsJs " 077-(0.45) Tb Lb GbJb 75×10 6 x πTds² 0.4315 32 2 75X106X Tids² 32 0315 x 32 GS 75MPa Gb = 40MP : db = • 90mm ds = ? 0.37 + ( 2 ) T 40x106x 7d2b = 0-6 11 75x106x πds 2 10.08 32 40×106x πdb² 32 11 75 X 10.6 x πids 2 0-6x32 40 x 106 x 71 x0.092 19.2 400106 XA CO09) 10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052 ds = 47.62mm X 65.47mm

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Shaft ABC comprises a brass section AB and a steel section BC with different diameters shown in the diagram below. A lever is located at B with a force F applied at its end. What is the required diameter of the steel section in order to support 70% of the total applied torque to the shaft given the following parameters: d₁ = 90mm Gs = 75MPa Gb === 40MPa Give your answer in mm. T 2m B 0.45m A C dp ds
Transcribed Image Text:Shaft ABC comprises a brass section AB and a steel section BC with different diameters shown in the diagram below. A lever is located at B with a force F applied at its end. What is the required diameter of the steel section in order to support 70% of the total applied torque to the shaft given the following parameters: d₁ = 90mm Gs = 75MPa Gb === 40MPa Give your answer in mm. T 2m B 0.45m A C dp ds
A 2M B 0.45 Steel brass 701 Torque supponed by steel TS = 0.7TT Total :. Tb = 0·35+ Torque OAC = 0 BC + OAB OAC = 0 · OBC = OAB Ts Ls GsJs " 077-(0.45) Tb Lb GbJb 75×10 6 x πTds² 0.4315 32 2 75X106X Tids² 32 0315 x 32 GS 75MPa Gb = 40MP : db = • 90mm ds = ? 0.37 + ( 2 ) T 40x106x 7d2b = 0-6 11 75x106x πds 2 10.08 32 40×106x πdb² 32 11 75 X 10.6 x πids 2 0-6x32 40 x 106 x 71 x0.092 19.2 400106 XA CO09) 10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052 ds = 47.62mm X 65.47mm
Transcribed Image Text:A 2M B 0.45 Steel brass 701 Torque supponed by steel TS = 0.7TT Total :. Tb = 0·35+ Torque OAC = 0 BC + OAB OAC = 0 · OBC = OAB Ts Ls GsJs " 077-(0.45) Tb Lb GbJb 75×10 6 x πTds² 0.4315 32 2 75X106X Tids² 32 0315 x 32 GS 75MPa Gb = 40MP : db = • 90mm ds = ? 0.37 + ( 2 ) T 40x106x 7d2b = 0-6 11 75x106x πds 2 10.08 32 40×106x πdb² 32 11 75 X 10.6 x πids 2 0-6x32 40 x 106 x 71 x0.092 19.2 400106 XA CO09) 10.08 x 40×106 XπT(0.09)² = 19.2 (75×106) x 77052 ds = 47.62mm X 65.47mm
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